CODEWITHSUNDEEP
java
Mo7
Mo7

Reputation: 27

I'm trying to find if more than one word exist from text file in my arraylist(GridWord)

int count = 0;
for (int i =0; i <8635; i++){
  
    try {
        line = Files.readAllLines(Paths.get("wordlist.txt")).get(i);
        if (GridWords.contains(line)){
            count++;
        }
        if (count > 1) { 
        ChoseRandomWord(randomword );
        RemoveTheSimilarLetters(randomword, letters25 );
        CreateTheGridContents(letters25, GridMap1, GridMap2);
        ValidationOfTheGrid(GridMap1, GridMap2);
        AskingTheUser(GridMap1, GridMap2);
        
        }
    } catch (IOException e) {
        System.out.println(e);
    }

}

I'm trying to check if what I did is the right way and why it kind of slow down the compiler when executing the program.

Upvotes: 0

Views: 40

Answers (1)

f1sh
f1sh

Reputation: 11943

I suspect you want something like this:

int count = 0;
List<String> lines;
try {
    lines = Files.readAllLines(Paths.get("wordlist.txt"));
} catch(IOException e) {
    e.printStackTrace();
    lines = Collections.emptyList();
    // or return;
}
for (int i =0; i < lines.size(); i++){
    String line = lines.get(i);
    if (GridWords.contains(line)){
        count++;
    }
}
if (count > 1) {
    ChoseRandomWord(randomword);
    RemoveTheSimilarLetters(randomword, letters25 );
    CreateTheGridContents(letters25, GridMap1, GridMap2);
    ValidationOfTheGrid(GridMap1, GridMap2);
    AskingTheUser(GridMap1, GridMap2);
}

This first counts the gridwords, then does the remaining logic. However your code is not doing anything with count other than making sure at least 2 words were found.

Upvotes: 1

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