Reputation: 678
I want to list all items in my template, but I want to list items under the same year. For example, under the 2021 title, model objects for that year should be listed. Year titles should come dynamically. How can I do it?
views.py
def press_list(request):
press_contents = PressContent.objects.all().order_by('-date')
context = {
'press_contents': press_contents
}
return render(request, "press_list.html", context)
models.py
class PressContent(models.Model):
label = models.CharField(max_length=500)
url = models.URLField(max_length=500)
date = models.DateTimeField(blank=True, null=True)
press_list.html
{% for press in press_contents %}
<div class="card" style="width: 18rem; margin:15px">
<div class="card-header">
{{ press.date.year }}
</div>
<ul class="list-group list-group-flush">
<li class="list-group-item"><a href="{{ press.url }}">{{ press.label }}</a></li>
# Other objects from this year should come here.
</ul>
</div>
{% endfor %}
To be clear: 2021
Upvotes: 1
Views: 119
Reputation: 476574
You can work with the {% regroup … by … %}
template tag [Django-doc]:
{% regroup press_contents by year as pressitems %}
{% for pressyear in pressitems %}
<div class="card" style="width: 18rem; margin:15px">
<div class="card-header">
{{ pressyear.grouper }}
</div>
<ul class="list-group list-group-flush">
{% for press in pressyear.list %}
<li class="list-group-item"><a href="{{ press.url }}">{{ press.label }}</a></li>
# Other objects from this year should come here.
{% endfor %}
</ul>
</div>
{% endfor %}
Upvotes: 3
Reputation: 8192
If you can afford to convert a queryset into a list of objects, then you can use the built-in template filter regroup (I think, I've never used it).
Another approach would be to write a python generator function and pass it in the context, to be iterated over by the template. This avoids issues with resource consumption when the queryset comprises a large number of objects. Something like
def year_grouper():
qs = PressContent.objects.all().order_by('-date')
last_object_year = 1000000000
for obj in qs:
obj.year_changed = ( obj.date.year != last_object_year )
yield obj
last_object_year = obj.date.year
and
{% for obj in year_grouper %}
{% if obj.year_changed %}
... year header, etc.
{% endif %}
... display obj
{% endfor %}
Upvotes: 1