CODEWITHSUNDEEP
xmlxslt
Tần Quảng
Tần Quảng

Reputation: 117

apply-templates not processed child nodes in order of select attribute

I want to format the number and rearrange the child nodes about the same format.

This is XML:

<?xml version="1.0" encoding="utf-8"?>
<include>
    ...
    <data>
        <id>10001</id>
        <name>Archery classroom</name>
        <level>0</level>
        <description_5>Primary archery class.</description_5>
        <maxLevel>8</maxLevel>
        <skillRank>1</skillRank>
        <coolDownTime>6000</coolDownTime>
        <needMoney>5980</needMoney>
        <needSkillPoint>2</needSkillPoint>
        <skillUnitDataID>10001</skillUnitDataID>
        <icon>28</icon>
        <description_2>3</description_2>
        <coolDownID>10001</coolDownID>
    </data>
    <data>
        <id>10002</id>
        <name>Archery classroom</name>
        <level>1</level>
        <maxLevel>8</maxLevel>
        <skillRank>1</skillRank>
        <coolDownID>10002</coolDownID>
        <skillUnitDataID>10002</skillUnitDataID>
        <needMoney>15980</needMoney>
        <needSkillPoint>2</needSkillPoint>
        <coolDownTime>16000</coolDownTime>
        <icon>28</icon>
        <description_2>3</description_2>
        <description_3>11</description_3>
        <description_5>Primary archery class.</description_5>
    </data>
    ...
</include>

I want to separate the group for thousands for coolDownTime and rearrange the child nodes according to the same order: id -> name -> level -> maxLevel -> skillRank -> needMoney -> needSkillPoint -> coolDownID -> coolDownTime -> skillUnitDataID -> description_1 -> description_2 -> description_3 -> description_4 -> description_5 -> icon.

This is the XSL code I used to do this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0">
    <xsl:output indent="yes" omit-xml-declaration="yes" method="xml"/>
    <xsl:strip-space elements="*"/>
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="data">
        <xsl:copy>
            <xsl:apply-templates select="id|name|level|maxLevel|skillRank|needMoney|needSkillPoint|coolDownID"/>
            <coolDownTime>
                <xsl:value-of select="format-number(coolDownTime,'#,000.#######')"/>
            </coolDownTime>
            <xsl:apply-templates select="skillUnitDataID|description_1|description_2|description_3|description_4|description_5|icon"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

But the results I received only coolDownTime were formatted group separation for thousands, the child nodes didn't arrange in the order that I was predetermined.

It seems that the code I wrote wasn't exactly somewhere.

So I'm very pleased with the suggestions you give.

Upvotes: 0

Views: 45

Answers (1)

Martin Honnen
Martin Honnen

Reputation: 167571

Use the "comma operator" , to select items in a certain order (e.g. id, name, level), not the union operators | which forms sequences of nodes sorted in document order.

Upvotes: 1

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