Reputation: 25
I have a data.frame with 150 column names. For each column, I want to extract the maximum and minimum values (the rows repeat) and the row names of each maximum value. I have extracted the min and max values in another data.frame but don't know how to match them.
I have found functions that are very close for this, like for minimum values:
head(cars)
speed dist
1 4 2
2 4 10
3 7 4
4 7 22
5 8 16
6 9 10
sapply(cars,which.min)
speed dist
1 1
Here, it only gives the first index for minimum speed.
And I've tried with loops like:
for (i in (colnames(cars))){
print(min(cars[[i]]))
}
[1] 4
[1] 2
But that just gives me the minimum values, and not if they are repeated and the rowname of each repeated value.
I want something like:
min.value column rowname freq.times
4 speed 1,2 2
2 dist 1 1
Thanks and sorry if I have orthography mistakes. No native speaker
Upvotes: 0
Views: 1365
Reputation: 78927
Here is another tidyverse
approach:
which.min(.)
gives the first index, whereas which(. == min(.))
will give all indices that are true for the condition!
Analogues to get the frequence we could use: length(which(.==min(.)))
summarise
across all columns min.value
, rowname
and freq.time
library(tidyverse)
cars %>%
summarise(across(dplyr::everything(), list(min.value = min,
rowname = ~list(which(. == min(.))),
freq.times = ~length(which(.==min(.)))))) %>%
pivot_longer(
cols = contains("_"),
names_to = "key",
values_to = "val",
values_transform = list(val = as.character)
) %>%
separate(key, c("column", "name"), sep="_") %>%
pivot_wider(
names_from = name,
values_from = val
) %>%
mutate(rowname = str_replace(rowname, '\\:', '\\,'))
column min.value rowname freq.times
<chr> <chr> <chr> <chr>
1 speed 4 1,2 2
2 dist 2 1 1
Upvotes: 2
Reputation: 8844
You can use which
to obtain the positions. sapply
should work. Since you need multiple summary statistics for each column, you just have to wrap up them in a list. Something like this
as.data.frame(sapply(cars, \(x) {
extrema <- range(x)
min.row <- which(x == extrema[[1L]])
max.row <- which(x == extrema[[2L]])
list(
min.value = extrema[[1L]], max.value = extrema[[2L]],
min.row = min.row, max.row = max.row,
freq.min = length(min.row), freq.max = length(max.row)
)
}))
Output
speed dist
min.value 4 2
max.value 25 120
min.row 1, 2 1
max.row 50 49
freq.min 2 1
freq.max 1 1
Upvotes: 1
Reputation: 16856
One option is to use tidyverse
. I was a little unclear if you want min
and max
in the same dataframe, so I included both. First, I create an index column with row numbers. Then, I pivot to long format to determine which values are minimum and maximum (using case_when
). Then, I drop the rows that are not min or max (i.e., NA
in category). Then, I use summarise
to turn the row names into a single character string and get the frequency of a given minimum or maximum value.
library(tidyverse)
cars %>%
mutate(rowname = row_number()) %>%
pivot_longer(-rowname, names_to = "column", values_to = "value") %>%
group_by(column) %>%
mutate(category = case_when((value == min(value)) == TRUE ~ "min",
(value == max(value)) == TRUE ~ "max")) %>%
drop_na(category) %>%
group_by(column, value, category) %>%
summarise(rowname = toString(rowname), freq.times = n()) %>%
select(2:3, 1, 4, 5)
Output
# A tibble: 4 × 5
# Groups: column, value [4]
value category column rowname freq.times
<dbl> <chr> <chr> <chr> <int>
1 2 min dist 1 1
2 120 max dist 49 1
3 4 min speed 1, 2 2
4 25 max speed 50 1
However, if you want to produce the dataframes separately. Then, you could adjust something like this. Here, I don't use category
and instead use filter
to drop all rows that are not the minimum for a group/column. Then, we can summarise
as we did above. You can do the samething for max
as well.
cars %>%
mutate(rowname = row_number()) %>%
pivot_longer(-rowname, names_to = "column", values_to = "min.value") %>%
group_by(column) %>%
filter(min.value == min(min.value)) %>%
group_by(column, min.value) %>%
summarise(rowname = toString(rowname), freq.times = n()) %>%
select(2, 1, 3, 4)
Output
# A tibble: 2 × 4
# Groups: column [2]
min.value column rowname freq.times
<dbl> <chr> <chr> <int>
1 2 dist 1 1
2 4 speed 1, 2 2
Upvotes: 2
Reputation: 8107
min.value <- sapply(cars, min)
columns <- names(min.value)
row.values <- sapply(columns, \(x) which(cars[[x]] == min.value[which(names(min.value) == x)]))
freq.times <- sapply(row.values, length)
row.values <- sapply(row.values, \(x) paste(x, collapse = ","))
names(min.value) <- names(row.values) <- names(freq.times) <- NULL
data.frame(min.value = min.value,
columns = columns,
row.values = row.values,
freq.times = freq.times)
min.value columns row.values freq.times
1 4 speed 1,2 2
2 2 dist 1 1
Here it is wrapped in function, so that you can use it across whatever data frame and function you need:
create_table <- function(df, FUN) {
values <- sapply(df, FUN)
columns <- names(values)
row.values <- sapply(columns, \(x) which(df[[x]] == values[which(names(values) == x)]))
freq.times <- sapply(row.values, length)
row.values <- sapply(row.values, \(x) paste(x, collapse = ","))
names(values) <- names(row.values) <- names(freq.times) <- NULL
data.frame(values = values,
columns = columns,
row.values = row.values,
freq.times = freq.times)
}
create_table(cars, min)
values columns row.values freq.times
1 4 speed 1,2 2
2 2 dist 1 1
create_table(cars, max)
values columns row.values freq.times
1 25 speed 50 1
2 120 dist 49 1
Upvotes: 2