CODEWITHSUNDEEP
pythonpython-3.x
Zakaria Hamane
Zakaria Hamane

Reputation: 67

Replacing If/Else Statements Python

I want to make a tic tac toe game user enter input one line string of all columns and rows of Xs and Os like this 'O_OOXOOXX' i turn them into nested list like this [['O', '_', 'O'], ['O', 'X', 'O'], ['O', 'X', 'X']]

My question is how can replace all the if elif below? because it seems a lot.

for i in range(3):
   if nested_list[i][0] == nested_list[i][1] == nested_list[i][2] == 'O':
      print('O wins')
   elif nested_list[0][i] == nested_list[1][i] == nested_list[2][i] == 'O':
      print('O wins')
   elif nested_list[0][0] == nested_list[1][1] == nested_list[2][2] == 'O':
      print('O wins')
   elif nested_list[0][2] == nested_list[1][1] == nested_list[2][0] == 'O':
      print('O wins')

   elif nested_list[i][0] == nested_list[i][1] == nested_list[i][2] == 'X':
      print('X wins')
   elif nested_list[0][i] == nested_list[1][i] == nested_list[2][i] == 'X':
      print('X wins')
   elif nested_list[0][0] == nested_list[1][1] == nested_list[2][2] == 'X':
      print('X wins')
   elif nested_list[0][2] == nested_list[1][1] == nested_list[2][0] == 'X':
      print('X wins')

Upvotes: 0

Views: 311

Answers (2)

Zakaria Hamane
Zakaria Hamane

Reputation: 67

I figured another solution:

arr = ['X', 'X', 'O', 'O', 'O', 'X', 'X', 'O', 'X']

I determine a nested list of possible wins

matches = [[0, 1, 2], [3, 4, 5],
           [6, 7, 8], [0, 3, 6],
           [1, 4, 7], [2, 5, 8],
           [0, 4, 8], [2, 4, 6]]

for i in range(8):
if(arr[matches[i][0]] == 'X' and
   arr[matches[i][1]] == 'X' and
   arr[matches[i][2]] == 'X'):
     print(X wins)
else:
  print(O wins)

and now i'm trying to figure out the other possibilities for example if the game not finished if the there is 3 Xs and Os in row then the game is impossible...

Upvotes: 0

sagi
sagi

Reputation: 40481

Probabily there's a nicer solution, but maybe something like this?

for i in range(3):
    a = set(nested_list[i,:])
    b = set(nested_list[:,i])
    if(len(a) == 1 && nested_list[i,0] != '_')
        print(nested_list[i,0], " wins")
    elif(len(b) == 1 && nested_list[0,i] != '_')
        print(nested_list[0,i], " wins")
if (((nested_list[0][0] == nested_list[1][1] == nested_list[2][2]) || nested_list[2][0] == nested_list[1][1] == nested_list[0][2])) && nested_list[1][1] != '_'):
    print(nested_list[1][1], " wins")

Upvotes: 1

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