Reputation:
Im trying to open a csv file as followed
My ipynb-file is in the following directory -> /data/filename.ipynb
where as my csv file is in the following directory -> /data/preprocessed/processed_data.csv
When i try to open the file with the following code:
df = pd.read_csv('/preprocessed/processed_data.csv')
I get an exception that the file doesn't exist. Somehow I think I didn't quite understand how the directories work. Please help, thanks.
Upvotes: 3
Views: 1865
Reputation: 959
Try using the os
module with a relative path:
import os
filename = os.path.join(os.path.dirname(__file__),'path/to/file/processed_data.csv')
df = pd.read_csv(filename)
Upvotes: 0