Reputation: 1
submitting a dynamic form but can't store the value to database. im a beginner i stuck for 2,3 days but cant solve the problem.
the request value is like {"_token":"PTGmyf3UZrD1TgKDJcREcKia9VFRLYaP5kNaAkAU","id":["28","31"],"name":["Fogg","zack"],"rate":["70","5000"],"quantity":["1","1"],"submit":"Submit"}
<form name="" id="form" action="{{ url('/store_order_item') }}" method="POST">
@csrf
<table class="table table-bordered" id="dynamic_field">
<thead>
<tr>
<th>Product Id</th>
<th>Name</th>
<th>Rate</th>
<th>Quantity</th>
<th>Amount</th>
<th>Action</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
<h6>Grand Total: <span id= "grandtotal"></span> </h6>
<input type="button" name="" id="" class="btn btn-sm btn-danger" value="Cancel">
<input type="submit" name="submit" id="submit" class="btn btn-sm btn-secondary" value="Submit"/>
</form>
</div>
<script type="text/javascript">
var i = 1;
$(document).ready(function(){
var button_id1 ;
$('#button').click(function(){
let namesearch = $('#search').val();
let idsearch = $('#idsearch').val();
if ((namesearch == '')&&(idsearch == '')){
return false;
}
$.ajax({
type:"GET",
url: "/pos_search_ajax",
data: { name: namesearch, id: idsearch },
success: function(response) {
$('#dynamic_field').append('<tr id="row_'+i+'"><td><input id="id_'+i+'" type="text" name="id[]" value="'+response[0].id+'" readonly></td><td><input id="name_'+i+'" name="name[]" type="text" value="'+response[0].name+'" readonly></td><td> <input id="rate_'+i+'" name="rate[]" type="text" value="'+response[0].price+'" readonly></td><td><input id="quantity_'+i+'" onchange="change('+i+')" name="quantity[]" type="number" min=1 value="1"></td><td class="total" id="total_'+i+'" name="total[]">'+response[0].price+'</td><td> <button type="button" onclick="remove_tr('+i+')" class="btn btn-danger btn-sm">Delete</button></td></tr>');
total();
i++;
}
});
# this is the Controller #
public function store(Request $request)
{
foreach($request->all() as $itm)
{
$items = New OrderItem();
$items->product_id = $request->id;
$items->name = $request->name;
$items->save();
}
}
Upvotes: 0
Views: 586
Reputation: 329
In case your request
always formatted like that, then using foreach($request->all() as $itm)
will only return what you send, value of id
will be ["28","31"]
and so on. So you could try something like this:
$data = $request->all();
for ($i=0; $i < count($data['id']); $i++) {
$item = new OrderItem();
$item->product_id = $data['id'][$i];
$item->name = $data['name'][$i];
$item->save();
}
That code will iterate over an id
, and the product name must be in the same order as the id.
Upvotes: 2
Reputation: 484
Multiple request parameter with same name needs additional array symbol([]
) on its name attirbute, and u did it right way like <input name="name[]" ...
.
This makes parameter that is array. (not a single value)
So u when u access the parameter, u need to access 1 more depth using index number(to get nth item).
To access all the items, u need to loop that parameter.
And parameters is not only one(id
, name
, rate
, quantity
), it is need that a parameter to be basis to loop.
The basis parameter could be anything, but normally identifiers preferred. (eg, id)
And the code to write ur own is something like @TheArka's answer. But recommend u know how's going on, why does it do.
Upvotes: 0