CODEWITHSUNDEEP
angularag-grid
Rich
Rich

Reputation: 1635

Is there a clean way to get the number of displayed rows EXCLUDING displayed detail (aka, children) rows in ag-grid?

Previously, I have used this.gridApi.getDisplayedRowCount(). However, I recently implemented a Master/Detail record structure for one of my grids and I have found that getDisplayedRowCount() is counting the children Detail records as displayed rows.

For example, if I have a table that contains 10 rows, then this.gridApi.getDisplayedRowCount() would return 10. Displaying the Details for one of the rows increases that return value to 11.

This isn't behavior that I want, so is there a way to just get the displayed rows, excluding detail rows?

Looking through the gridApi object, I have found a way to do it, but I don't really like that I am accessing nested objects without using the provided API.

this.gridApi.rowModel.rowsToDisplay.filter(row => !row.detail).length; -> 10

Upvotes: 2

Views: 1499

Answers (1)

Rich
Rich

Reputation: 1635

gridApi.forEachNode() and gridApi.forEachNodeAfterFilter() both appear to skip detail rows while iterating thru row data, so for now, this is the approach that I am following to get this data.

I have replaced my gridApi call to get the displayed row count with a custom function to count the nodes we visit using forEachNodeAfterFilter..

  getDisplayedRowCount(){
    let count = 0;
    this.gridApi.forEachNodeAfterFilter(() => count++);
    return count;
  }

Upvotes: 2

Related Questions