CODEWITHSUNDEEP
bash
user8801226
user8801226

Reputation: 15

Prevent grep from exiting in case of nomatch

Prevent grep returning an error when input doesn't match. I would like it to keep running and not exit with exit code: 1

set -euo pipefail
numbr_match=$(find logs/log_proj | grep "$name" | wc -l);

How could I solve this?

Upvotes: 0

Views: 1074

Answers (2)

user1934428
user1934428

Reputation: 22301

I don't know why you are using -e and pipefail when you don't want to have this behaviour. If your goal is just to treat exit code 2 (by grep) as error, but exit code 1 as no-error, you could write a wrapper script around grep, which you call instead of grep:

#!/bin/bash
# This script behaves exactly like grep, only
# that it returns exit code 0 if there are no
# matching lines
grep "$@"
rc=$?
exit $((rc == 1 ? 0 : rc))

Upvotes: 0

tripleee
tripleee

Reputation: 189749

In this individual case, you should probably use

find logs/log_proj -name "*$name*" | wc -l

More generally, you can run grep in a subshell and trap the error.

find logs/log_proj | ( grep "$name" || true) | wc -l

... though of course grep | wc -l is separately an antipattern;

find logs/log_proj | grep -c "$name" || true

Upvotes: 1

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