CODEWITHSUNDEEP
anylogic
TRUESIM
TRUESIM

Reputation: 69

Anylogic: Queue timeout & condition

In the default settings it is possible to set a time in the queue after which an agent leaves the queue via outTimeOut. However, only a fixed time can be entered in the corresponding field, e.g. 12 hours. Is there a possibility to link these 12 hours with a condition? In my case, the agent should only leave the queue after 12 hours via outTimeOut if a certain condition is also met. In my case, if a variable varIN == 1.

Upvotes: 1

Views: 817

Answers (2)

Benjamin
Benjamin

Reputation: 12660

You can use a function (returning a double) to define and calculate the most complex logic you like. If you provide an argument of type Agent (or the specific agent type flowing through the blocks), it can even account for your agent characteristics.

In the queue block timeout, simply call the function.

Upvotes: 0

Yashar Ahmadov
Yashar Ahmadov

Reputation: 1636

Collect the time in queue statistics for each agent. Create a parameter called entryTime. When they enter the block, set agent.entryTime=time();

You can create an event that iterates through the queue every 1 second and removes the agents that meet your conditions from the queue (by using remove(Agent agent) function). That means if (time()-agent.entryTime>12)&&(agent.varIN==1), you will remove that agent.

Loop will look like this:

for (int i=0; i< yourQueue.size(); i++) {
    YourAgentType currentAgent = ((YourAgentType)yourQueue.get(i));

   if ((time()-currentAgent.entryTime>12)&&(currentAgent.varIN==1)){
     yourQueue.remove(currentAgent);
}
}

Upvotes: 2

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