CODEWITHSUNDEEP
pythonpython-3.xpython-idle
Yılmaz Alpaslan
Yılmaz Alpaslan

Reputation: 359

How can I open the currently running script's .py file using IDLE in Python?

In a GUI app written in Python and Tkinter, I want to add a menu command which will open the source code of the *.py file in IDLE. I also want it to be platform independent.

I've tried using os.system to open IDLE from Scripts folder of Python, but that would be platform dependent. I couldn't find a way to get the Scripts folder of Python to make it independent. How can I achieve this?

Upvotes: 1

Views: 399

Answers (2)

Umekokoko
Umekokoko

Reputation: 1

I tried some special way:

    import idlelib.pyshell
    import sys
    sys.argv.clear()
    sys.argv.append("")
    sys.argv.append(fName)
    idlelib.pyshell.main()

It works! But I don't know whether this way will generate some problems.

Upvotes: 0

Terry Jan Reedy
Terry Jan Reedy

Reputation: 19144

To open a file in an IDLE editor, the command line is

<python> -m idlelib <path>

where <python> is the full path to a python executable or a name that resolves to such. If you want to open IDLE with the same python that is running you python app, which is likely what you want, use the platform-independent sys.executable. The path to the source code for the running app is __file__. This is one of the semi-hidden global variables when python runs a file. Or give the path to any other file.

Whether you use os.system or subprocess is a different issue. The latter is more flexible. subprocess.run replaces os.system. subprocess.Popen should not block. IDLE uses the latter to run user code.

Upvotes: 2

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