Reputation: 83
I have line and circle model (I know the equation that is formed by using data). I would like to find tangent points or equation of yellow circle (radius is determined by me) which tangent with my line and circle.
At the beginning I tried to solve mutual equation separately line and yellow circle and circle and yellow circle reduce to 3 equation to 2 equation but I couldn't find a solution maybe calculation error.
Is there any more clear way or opinion to find these points by python?
For example:
Circle-1: (x-8,98)^2 + (y-42,53)^2 = 6,4^2
Line-1: y=22,904x-115,9707
Tangent Circle:(x-a)^2 + (y-b)^2 = 14^2
Tangent points (Founded in AutoCAD):
X1=6,2028 Y1=26,0978
X2=12,4953 Y2=37,1832
Upvotes: 1
Views: 1070
Reputation: 126
Your problem has multiple solutions.
You have 6 unknowns, so the simplest way to solve the problem (not necessarily the fastest) is to craft 6 equations using the constraints defined. After that, you can use a symbolic Math engine like Sympy to solve the system of equations.
Let's start by defining the equations.
We have finally the 6 equations, so we can use Sympy to solve the system of equations.
I recommend running the following code on a Jupyter notebook
#%%
#imports
import sympy as sp
from sympy import Eq
from sympy.physics.mechanics import dynamicsymbols
from sympy.physics.vector import init_vprinting
init_vprinting(use_latex='mathjax', pretty_print=False)
#%%
#Unknows and variables definition
x_a1, y_a1, r_1, r_2, a, b = 8.98, 42.53, 6.4, 14, 22.904, -115.97
x_a2, y_a2, x_p1, y_p1, x_p2, y_p2 = dynamicsymbols('x_a2 y_a2 x_p1 y_p1 x_p2 y_p2')
#%%
#equations definition
eq1 = Eq(y_p1-y_a2,(1/a)*(x_a2-x_p1))
eq2 = Eq((x_p1-x_a2)**2+(y_p1-y_a2)**2,r_2**2)
eq3 = Eq(y_p1, a * x_p1 + b)
eq4 = Eq((x_a2-x_a1)**2+(y_a2-y_a1)**2,(r_1 + r_2)**2)
eq5 = Eq((x_p2-x_a1)**2+(y_p2-y_a1)**2,r_1**2)
eq6 = Eq((x_p2-x_a2)**2+(y_p2-y_a2)**2,r_2**2)
eq4 = sp.expand(eq4)
eq5 = sp.expand(eq5)
#%%
#solve the system
sp.solve((eq1,eq2,eq3,eq4,eq5,eq6), (x_a2, y_a2, x_p1, y_p1, x_p2, y_p2))
Here are the solutions (in this order: [x_a2, y_a2, x_p1, y_p1, x_p2, y_p2]) I got,
[(−7.61137900888098, 30.6604531432888, 6.37529636566885, 30.0497879592794, 3.77486148740989, 38.8062205939729), (−6.51375646949495, 55.8003997853864, 7.47291890505488, 55.1897346013771, 4.11921365662903, 46.6932626777683), (20.1893606892033, 25.4856392628135, 6.20268531465346, 26.0963044468229, 12.496662177005, 37.1827495726474), (21.6322053306201, 58.5325529298243, 7.64552995607028, 59.1432181138336, 12.9493193194102, 47.5504087622978)]
The third solution is the one given by AutoCAD (and the one represented in your figure)
Upvotes: 3