CODEWITHSUNDEEP
pythonpandasdataframe
Lumos
Lumos

Reputation: 1383

TypeError: 'float' object is not iterable in logical operation

In a dataframe. each row in column B contains a list, which is stored in object data type. I want to compare each row in B with another list. If they are equal in value, I want to add a new column indicting TRUE, otherwise, FALSE.

df 

B
"1st", "2nd", "3rd"
"2nd", "1st", "4th"
"1st", "2nd", "3rd"

I use iterrows() for looping into rows:

for index, row in df[['B']].iterrows():
    set(row['B']) == set(['1st', '2nd', '3rd'])

The error shows TypeError: 'float' object is not iterable, but I don't have any numeric in the comparison, why does it happen? Also, if I print(set(row['B']) == set(['1st', '2nd', '3rd'])), it shows TRUE/FALSE. Why is that?

Upvotes: 0

Views: 291

Answers (1)

user7864386
user7864386

Reputation:

That error indicates that there are some NaN values in "B". See if

len(df['B']) == len(df['B'].dropna())

is True.

Also instead iterrows, you can use list comprehension where you check if you have a list or not:

df = pd.DataFrame({'B':[["1st", "2nd", "3rd"], ["2nd", "1st", "4th"], ["1st", "2nd", "3rd"], np.nan]})
df['new_col'] = [set(x)==set(['1st', '2nd', '3rd']) if isinstance(x, list) else False for x in df['B']]

Output:

  new_col
0   True
1  False
2   True
3  False

Upvotes: 1

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