CODEWITHSUNDEEP
javascriptelasticsearchelastic-stack
Psy
Psy

Reputation: 184

Getting only the insides of the source from the elastic search query

What im trying to do is to get only the source from the elastic search query in order to skip the processing on the javascript, so i could squize some more performance gains.Is it possible to do so?

So here is what i currenly do, i just get the data from the elastic search and iterate every one of those objects in order to construct an array that only contains the what's inside of _source: 

const { body } = await this.elsticSearchService.search<any>({
 index: this.configService.get('ELASTICSEARCH_INDEX'),
 body: {
 query: {
    match_all: {},
    },
    size: 10000,
  },
});

const hits = body.hits.hits;

return hits.map((item: any) => item._source);

So my question is, is there a way to only get the _source from the elastic search, in order to skip the processing on the JavaScript? So the object returned from the elastic search would look like this

[
0:{ "key": "value"}, // key,value from _source object
1:{ "key": "value"}, // key,value from _source object
2:{ "key": "value"}, // key,value from _source object
]

so without all of the other fields like hits, took etc...

Upvotes: 0

Views: 821

Answers (1)

Val
Val

Reputation: 217344

It's not possible to change the structure of the response you get from the search call.

However, what you can do is to specify filter_path so you only get the _source content in the response and you wouldn't need to process it since you know you only have _source content

const { body } = await this.elsticSearchService.search<any>({
 index: this.configService.get('ELASTICSEARCH_INDEX'),
 filter_path: '**._source',         <--- add this line
 body: {
 query: {
    match_all: {},
    },
    size: 10000,
  },
});

Upvotes: 1

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