Giuseppe Mondelli
Giuseppe Mondelli

Reputation: 45

How can I sort a Map<String, List<CustomObject>>?

I have done a lot of research for this question, but I have not found a way to sort a map of custom object lists (Map<String, List<CustomObj>>), basing the comparison on CustomObj attributes (as SORT_BY_NAME, SORT_BY_DATE, etc).

A motivating example of my question is:

For simplicity I report the real code but adapted to a simplified case of Person object, because it would already represent the concept of entity.

Person.java -> Custom object

public class Person {

     private String name;
     private Date dateOfBirth;
     ...

     // Empty and Full attrs Constructors
     ...

     // Getter and Setter
     ...

     // Comparator by name
     public static Comparator<Person> COMPARE_BY_NAME = Comparator.comparing(one -> one.name);
     // Comparator by date
     public static Comparator<Person> COMPARE_BY_DATE = Comparator.comparing(one -> one.dateOfBirth);

}

Sorter.java -> Sorter object

public class Sorter {

     // List Comparator of Person by Date 
     public static final Comparator<? super List<Person>> COMPARATOR_BY_DATE = (Comparator<List<Person>>) (p1, p2) -> {
          for (Persontab person1: p1) {
              for (Person person2: p2) {
                  return Person.COMPARE_BY_DATE.compare(person1, person2);
              }
          }
          return 0;
     };

     // List Comparator of Person by Name
     public static final Comparator<? super List<Person>> COMPARATOR_BY_NAME = (Comparator<List<Person>>) (p1, p2) -> {
          for (Persontab person1: p1) {
              for (Person person2: p2) {
                  return Person.COMPARE_BY_NAME.compare(person1, person2);
              }
          }
          return 0;
     };

     // Sorting method
     public Map<String, List<Person>> sort(Map<String, List<Person>> map, Comparator<? super List<Person>> comparator) {
          return map.entrySet()
            .stream()
            .sorted(Map.Entry.comparingByValue(comparator))
            .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (v1, v2) -> v1, LinkedHashMap::new));
     }

}

Main.java -> Start code

public class MainApp {

     public static void main(String[] args) {

          Map<String, List<Person>> exampleMap = new HashMap<>();
          List<Person> personList = new ArrayList<>();
          personList.add(new Person("name1", new Date("2022-01-01")));              
          personList.add(new Person("name12", new Date("2022-01-05")));
          personList.add(new Person("name13", new Date("2022-01-03")));
          map.put("2022-01", personList);

          personList.clear();
          personList.add(new Person("name14", new Date("2021-02-01")));              
          personList.add(new Person("name3", new Date("2021-02-05")));
          personList.add(new Person("name4", new Date("2021-02-03")));
          map.put("2021-02", personList);

          Sorter sorter = new Sorter();

          // Example of sorting by date
          map = sorter.sort(exampleMap, Sorter.COMPARATOR_BY_DATE);
          // In this case the sorting works correctly, or rather it sorts the items by date as I expect
         
          // Example of sorting by name
          map = sorter.sort(exampleMap, Sorter.COMPARATOR_BY_NAME);
          // In this case, I don't think sorting works correctly. Sort each list of elements for each key in ascending order. But it doesn't sort the map elements.

          /* I expect to have the following map when sort by date:
             "2021-02": [
               Person("name14", new Date("2021-02-01")),
               Person("name4", new Date("2021-02-03")),
               Person("name3", new Date("2021-02-05"))
             ], 
             "2022-01": [
               Person("name14", new Date("2021-02-01")),
               Person("name13", new Date("2022-01-03")),
               Person("name12", new Date("2022-01-05"))
             ]
             
     }

}

Upvotes: 3

Views: 1622

Answers (2)

Giuseppe Mondelli
Giuseppe Mondelli

Reputation: 45

By changing the type of Map used in my code above, as suggested by @Thomas, in TreeMap<>, I found the solution to the problem as follows:

  1. I first merged all the Person object lists into one list. This was then sorted by the chosen criterion, for example Person.COMPARE_BY_NAME;
  2. I created an algorithm that would re-group the sorted lists, in according to the criteria of my project, in a map. The key of this map corresponds to the concatenation of the month + year of the Person object. The algorithm is reported at the bottom of the comment;
  3. I sort the map based on the chosen attribute, for example Sorter.COMPARATOR_BY_NAME;

Di seguito il codice è come segue:

Merge all List<Person> in one -> main or somewhere before the Map was created

    ...
    //
    List<Person> newPersonList = new ArrayList<>();
    newPersonList.addAll(oldPersonList1);
    newPersonList.addAll(oldPersonList2);
    ...

Main or somewhere before the Map was created

    ...
    groupList(Person.COMPARE_BY_NAME, Sorter.COMPARATOR_BY_NAME);
    ...

GroupPerson -> method to group the merged List<Person> in a TreeMap<String, List<Person>>

    public Map<String, List<Person>> groupList(final Comparator<? super Person> itemComparator, final Comparator<? super List<Person>> listComparator)
         
         // Sort Person list by comparator before create TreeSet
         newPersonList.sort(itemComparator);

         Map<String, List<Person>> personMapGrouped = new TreeMap<>();
         
         // Here, create a Map of list
         for (Person person: newPersonList) {
             final SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy MM", Locale.getDefault());
             final String groupKey = dateFormat.format(person.getDateOfBirth());

             if (personMapGrouped.containsKey(groupKey)) {
                // The key is already in the TreeMap; add the Person object against the existing key.
                final List<Person> personListGrouped = personMapGrouped.get(groupKey);
                if (personListGrouped!= null) {
                   personListGrouped.add(person);
                }
             } else {
                // The key is not there in the TreeMap; create a new key-value pair
                final List<Person> personListGrouped = new ArrayList<>();
                personListGrouped.add(person);
                personMapGrouped.put(groupKey, personListGrouped);
             }
         }
         // Here sort the Map by params passed
         final TabPersonSorter sorter = new TabPersonSorter();
         personMapGrouped = sorter.sort(personMapGrouped, listComparator);
    }

In this case, using the lists created in the main above, the results obtained are:

    "List<Person> mergedList": [
        Person("name1", new Date("2022-01-01")),
        Person("name3", new Date("2021-02-05")),
        Person("name4", new Date("2021-02-03")),
        Person("name12", new Date("2022-01-05")),
        Person("name13", new Date("2022-01-03")),
        Person("name14", new Date("2021-02-01"))
    ]

    "Map<String, List<Person>> mergedMap": {
        "2022-01": [
            Person("name1", new Date("2022-01-01")),
            Person("name12", new Date("2022-01-05")),
            Person("name13", new Date("2022-01-03"))
        ], 
        "2021-02": [
            Person("name3", new Date("2021-02-05")),
            Person("name4", new Date("2021-02-03"))
        ],
        "2022-02": [
            Person("name14", new Date("2021-02-01"))
        ]
    } 

Obviously if the grouping in the map were not bound by such a restrictive date as only year + month, the sorting would have the desired effect in distinct groups. In fact, in the case of the sorting by date, this is respected very well.

Upvotes: 1

Thomas
Thomas

Reputation: 88707

First, let's reiterate: a HashMap is unordered so you need something else. Your Sorter.sort() method actually collects the values into a LinkedHashMap which provides an iteration order based on insert order and would be ok for your use case. Just to be clear (also for the sake of others): this doesn't sort the map itself but creates a new LinkedHashMap.

Now to your comparators: if you want to compare 2 lists you probably want to compare elements at equal indices. Thus your comparator needs to be something like this:

Comparator<List<Person>> = (l1, l2) -> {
   Iterator<Person> itr1 = l1.iterator();
   Iterator<Person> itr2 = l2.iterator();

   while( itr1.hasNext() && itr2.hasNext() ) {
     Person p1 = itr1.next();
     Person p2 = itr1.next();

     int result = Person.COMPARE_BY_DATE.compare(p1, p2);
     if( result != 0 ) {
       return result;
     }
   }

   return 0;
};
 

However, the lists might have different lengths as well so you might want to handle that too:

Comparator<List<Person>> = (l1, l2) -> {
   //iterators and loop here

   //after the loop it seems all elements at equal indices are equal too
   //now compare the sizes

   return Integer.compare(l1.size(), l2.size());
}

Upvotes: 1

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