CODEWITHSUNDEEP
pyqt5
urie
urie

Reputation: 371

pyqt5 - how to find menu in menubar:

I'm running a code that adds a menu to the toolbar. But when I run it again, it adds another menu to the toolbar with the same name.

How do I get rid of the first menu? I found "setVisible=True", but I don't know how to find the menu whom I should set this to. How can I achieve that?

Thanks!

def run(self)
     with open(menubar_file) as file:
            yaml_content = file.read()
            menu_dict = yaml.load(yaml_content, Loader=yaml.FullLoader)
     for menu, menubar_content in menu_dict.items():
            q_menubar = self.win.menubar.addMenu(menu). // How do I do "if self.win.menubar contains menu, delete(menu)?"
            # rest of code

Couldn't find it in the documentation... Thanks in advance!

Upvotes: 2

Views: 663

Answers (1)

musicamante
musicamante

Reputation: 48231

Every QWidget has a list of QActions, they are normally added using addAction() or addActions(), but QMenu and QMenuBar do that also when using addMenu().

Each QMenu also has a menuAction(), which is the action used when the menu is added to a QMenuBar or to QMenu as a sub menu.

Using actions() you can access the list of each action added to a certain widget, and in the case of QMenuBar it will list every menuAction() of each menu.

Note that:

  • you can add basic QActions to a QMenuBar (it will not be a menu, and clicking it will trigger the action);
  • adding actions to widgets doesn't change their ownership, as the same action can be shared between multiple widgets;
  • the opposite of menuAction() is menu(), which returns the QMenu associated with that action;

If you need to replace each existing menu based on its title, you can cycle through all actions, check if the name matches and it's a menu, and then clear it before replacing its contents:

def run(self)
    with open(menubar_file) as file:
        yaml_content = file.read()
        menu_dict = yaml.load(yaml_content, Loader=yaml.FullLoader)

    menus = {a.text():a.menu() for a in self.win.menubar.actions() if a.menu()}
    for menu_name, menubar_content in menu_dict.items():
        menu = menus.get(menu_name)
        if menu is None:
            self.win.menubar.addMenu(menu_name)
        else:
            menu.clear()
        # ...

Upvotes: 1

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