CODEWITHSUNDEEP
pythonpython-3.xdictionary
pirogan
pirogan

Reputation: 21

How to merge two dictionaries with the same keys and keep the larger value?

I have two dicts:

a = {'a': 1, 'b': 2, 'c': 3}
b = {'a': 2, 'd': 4, 'c': 5}

and I want to get:

{'a': 2, 'b': 2, 'c': 5}

I used {**a, **b} but it return:

{'a': 2, 'b': 2, 'c': 5, 'd': 4}

How to exclude keys from b which are not in a using the simplest and fastest way.

I am using python 3.7.

Upvotes: 0

Views: 139

Answers (3)

kasjhuyvALI7
kasjhuyvALI7

Reputation: 1

Try this:

a = {'a': 1, 'b': 2, 'c': 3}
b = {'a': 2, 'd': 4, 'c': 5}

result = {}

# Iterate over keys in dictionary a
for key, value in a.items():
    # If key exists in dictionary b, choose the maximum value
    if key in b:
        result[key] = max(value, b[key])
    else:
        result[key] = value

print(result)

This should also work:

result = {key: max(a.get(key, 0), b.get(key, 0)) for key in a}

print(result)

Upvotes: 0

JANO
JANO

Reputation: 3076

You have to filter the elements of the second dict first in order to not add any new elements. I got two possible solutions:

a = {'a': 1, 'b': 2, 'c': 3}
b = {'a': 2, 'd': 4, 'c': 5}

for k,v in b.items():
    if (k in a.keys()):
        a[k] = v

print(a)

a = {'a': 1, 'b': 2, 'c': 3}
b = {'a': 2, 'd': 4, 'c': 5}

a.update([(k,v) for k, v in b.items() if k in a.keys()])

print(a)

Output for both:

{'a': 2, 'b': 2, 'c': 5}

Upvotes: 2

kirjosieppo
kirjosieppo

Reputation: 647

I think a comprehension is easy enough:

{ i : (b[i] if i in b else a[i]) for i in a }

Upvotes: 2

Related Questions