Reputation: 5540
How to extract the text which is displayed as part of the link inside the span marker.
<span class="pull-left w-100 font30 medium_blue_type mb10"><a href='/XLY'>XLY</a></span> <span class="w-100">Largest Allocation</span>
Output:
XLY
I've tried several approaches, among all, using
elems = driver.find_elements_by_class_name("span.pull-left.w-100.font30.medium_blue_type.mb10")
elems = driver.find_element_by_xpath('.//span[@class = "pull-left w-100 font30 medium_blue_type mb10"]')
but can't get it working. The website is https://www.etf.com/stock/TSLA.
EDIT: Is it possible to do it without opening the window in the browser, e.g. using "headless" option?
op = webdriver.ChromeOptions()
op.add_argument('headless')
driver = webdriver.Chrome(CHROME_DRIVER_PATH, options=op)
Upvotes: 0
Views: 973
Reputation: 33384
Use the following xpath
to identify the href
link.
//div[./span[text()='Largest Allocation']]//a
You need to induce some delay to get the element.
Use WebDriverWait()
and wait for visibility of the element.
To get the text:
print(WebDriverWait(driver,10).until(EC.visibility_of_element_located((By.XPATH, "//div[./span[text()='Largest Allocation']]//a"))).text)
To get the href:
print(WebDriverWait(driver,10).until(EC.visibility_of_element_located((By.XPATH, "//div[./span[text()='Largest Allocation']]//a"))).get_attribute("href"))
you need to import below libraries.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
Upvotes: 0
Reputation: 29362
If you prefer to have a text-based locators, you can use the below:
//span[text()='Largest Allocation']/../span
So your effective code would be:
driver = webdriver.Chrome(driver_path)
driver.maximize_window()
wait = WebDriverWait(driver, 30)
driver.get("https://www.etf.com/stock/TSLA")
try:
wait.until(EC.element_to_be_clickable((By.LINK_TEXT, "I Understand"))).click()
print("Clicked on I understand button")
except:
pass
txt = wait.until(EC.visibility_of_element_located((By.XPATH, "//span[text()='Largest Allocation']/../span"))).text
print(txt)
Imports:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Output:
Clicked on I understand button
XLY
Process finished with exit code 0
If you are looking for locators not based on text, use the below line of code:
txt = wait.until(EC.visibility_of_element_located((By.XPATH, "(//span[contains(@class,'medium_blue_type')]//a)[2]"))).text
Upvotes: 1
Reputation: 33361
There are several possible problems here:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 20)
href = wait.until(EC.visibility_of_element_located((By.XPATH, "//span[@class = "pull-left w-100 font30 medium_blue_type mb10"]"))).get_attribute("href")
Upvotes: 0