Reputation: 3
Can someone help me convert the below XSLT 2.0 code to XSLT 1.0? Thanks.
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[E1EDL24]">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:for-each-group select="node()" group-adjacent="boolean(self::E1EDL24)">
<xsl:choose>
<xsl:when test="current-grouping-key()">
<xsl:apply-templates select="current-group()">
<xsl:sort select="MATNR" order="descending"/>
</xsl:apply-templates>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:transform>
Upvotes: 0
Views: 177
Reputation: 167716
Try whether the following works:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@*|node()" mode="sort">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:key name="adjacent-group" match="E1EDL24[preceding-sibling::*[1][self::E1EDL24]]" use="generate-id(preceding-sibling::E1EDL24[not(preceding-sibling::*[1][self::E1EDL24])][1])"/>
<xsl:template match="E1EDL24[not(preceding-sibling::*[1][self::E1EDL24])]">
<xsl:apply-templates select=". | key('adjacent-group', generate-id())" mode="sort">
<xsl:sort select="MATNR" order="descending"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="E1EDL24[preceding-sibling::*[1][self::E1EDL24]]"/>
</xsl:stylesheet>
Upvotes: 0