CODEWITHSUNDEEP
arrayscfor-loopif-statement
Haaland
Haaland

Reputation: 47

C program to search for a number and count its occurrences in an array

This code works in a wrong way, I am kind of finding the solution but I can't apply it. I want to separate a line of code that is outside the for loop but inside the if statement knowing that if statement is inside a nested loop.

I mean this line: printf("\n fianl result %d has appeard %d in the array", j, count);

int main() {
    int array[10];
    int i, j;
    int count = 0;

    printf("Enter numbers\n");
    for (i = 0; i <= 9; i++) {
        scanf("%d", &array[i]);
    }

    printf("Enter the number you are looking for:\n");
    scanf("%d", &j);
    for (i = 0; i <= 9; i++) {
        if (j == array[i]) {
            printf("%d is in the array it is in entery %d\n", j, i+1);
            count++;
            printf("\n fianl result %d has appeard %d in the array", j, count);
            printf("Enter another number \n");
            scanf("%d", &j);
        } else {
            printf("%d is not the array", j);
            printf("Enter another number");
            scanf("%d", &j);
        }
    }
    return 0;
}

Upvotes: 0

Views: 1416

Answers (1)

mmixLinus
mmixLinus

Reputation: 1714

You should move your scanfs out of the for loop so they aren't executed while you are scanning through the array. Entering -1 ends the while loop.

// your variables and array setup goes here
...
printf("Enter the number you are looking for:\n");
scanf("%d", &j);
while (j != -1) {
    int count = 0;
    for (i = 0; i <= 9; i++) {
        if (j == array[i]) {
            printf("%d is in the array it is in entery %d\n", j, i+1);
            count++;
        }
    }
    if (count == 0) {
        printf("%d is not the array", j);
    } else {
        printf("\n final result %d has appeared %d times in the array", j, count);
    }

    printf("Enter the number you are looking for:\n");
    scanf("%d", &j);
}

Upvotes: 1

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