CODEWITHSUNDEEP
pythonpandasmean
Lima
Lima

Reputation: 159

Finding the mean of nuisance columns in DataFrame error

      id gender status dept  var1  var2  salary
0   P001      M     FT   DS   2.0   8.0     NaN
1   P002      F     PT   FS   3.0   NaN    54.0
2   P003      M    NaN  AWS   5.0   5.0    59.0
3   P004      F     FT  AWS   NaN   8.0   120.0
4   P005      M     PT   DS   7.0  11.0    58.0
5   P006      F     PT  NaN   1.0   NaN    75.0
6   P007      M     FT   FS   NaN   NaN     NaN
7   P008      F    NaN   FS  10.0   2.0   136.0
8   P009      M     PT  NaN  14.0   3.0    60.0
9   P010      F     FT   DS   NaN   7.0   125.0
10  P011      M    NaN  AWS   6.0   9.0     NaN

print(df.mean())

FutureWarning: Dropping of nuisance columns in DataFrame reductions (with 'numeric_only=None') is deprecated; in a future version this will raise TypeError.  Select only valid columns before calling the reduction.
  print(df.mean())

when corrected my code as :

print(df.mean(numeric_only=True))

I solve it , without an error.

Is there any other way to solve it ?

Upvotes: 13

Views: 37112

Answers (2)

я яя
я яя

Reputation: 1

Try this:

import pandas as pd
pd.options.mode.chained_assignment = None

Upvotes: -1

user17242583
user17242583

Reputation:

No, there's no other way to solve it. Using numeric_only=True is the right way.

You're getting that warning because there are some columns that contain strings, but df.mean() only works with columns that contain numbers (floats, ints, nan, etc.).

Using numeric_only=True causes df.mean() to ignore columns that contain non-numbers, and only calculate the mean for columns that only contain numbers.

Upvotes: 21

Related Questions