CODEWITHSUNDEEP
pythonstringlist
Martin Kunze
Martin Kunze

Reputation: 1055

Python: converting list of strings into a string which illustrates the list

I'm searching a simple method for converting a list of strings (e.g. ['test 1', 'test 2' , 'test 3'] ) into a string whereby the list of objects doesn't have some quotation mark. That means in our example ('[test 1, test 2, test 3]'). My first approach was:

import json
A = ['test 1', 'test 2' , 'test 3']
test = json.dumps(A).replace('"', '')

Is their a more general way without that replace statement at the background? Cause my problem with that is, that e.g.

A = ['test 1', 'test 2' , 'test 3"AA"']

results in the string:

   '[test 1, test 2, test 3\AA\]'

and not the desired string:

'[test 1, test 2, test 3"AA"]'

Upvotes: 0

Views: 66

Answers (2)

SpacedOutKID
SpacedOutKID

Reputation: 155

A simple way you could try would be

A = ['test 1', 'test 2' , 'test 3"AA"'] #your list
print (*A, sep =', ')

Upvotes: 2

Corralien
Corralien

Reputation: 120469

Try f-strings:

>>> print(f"'[{', '.join(A)}]'")
'[test 1, test 2, test 3"AA"]'

# OR

>>> print(f"[{', '.join(A)}]")
[test 1, test 2, test 3"AA"]

Upvotes: 4

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