Reputation:
so I've combined those 2 rasters and made them into one dem raster which contains elevation values:
dem1 = read_stars("srtm_43_06.tif")
dem2 = read_stars("srtm_44_06.tif")
pol = st_read("israel_borders.shp")
dem = st_mosaic(dem1, dem2)
dem = dem[, 5687:6287, 2348:2948]
names(dem) = "elevation"
dem = st_warp(src = dem, crs = 32636, method = "near", cellsize = 90)
Now I need to calculate a point geometry of the peak of the mountain by finding the centroid of the pixel that has the highest elevation in the image, does anyone know what functions I can use?
Upvotes: 1
Views: 238
Reputation: 3604
Let's use terra
, however similar approach can be applied by raster
package as well. For testing purposes we will use raster supplied with terra
package
library(terra)
#> terra 1.5.12
f <- system.file("ex/elev.tif", package="terra")
v <- rast(f)
plot(v)
You can check the details of your raster just typing the raster object name and pressing enter, you can check the min
and max
values with minmax()
function form terra
:
minmax(v)
#> elevation
#> [1,] 141
#> [2,] 547
Let's create another raster by copying original one, however checking if the value is the max
value of elevation:
w <- v == minmax(v)[2]
plot(w)
Let's create a substitution matrix, and substitute all FALSE
with NA
and TRUE
with 1
:
mx <- matrix(c(FALSE, NA, TRUE, 1), ncol = 2, byrow = TRUE)
w <- classify(w, mx)
plot(v)
plot(as.polygons(w), add=TRUE)
Let's find centroids of those polygon(s):
pts <- centroids(as.polygons(w))
plot(pts, add=TRUE)
Let's see our coordinates:
as.data.frame(pts, geom = "WKT")
#> elevation geometry
#> 1 1 POINT (6.020833 50.179167)
Created on 2022-01-29 by the reprex package (v2.0.1)
Upvotes: 1
Reputation: 47156
Building on Grzegorz Sapijaszko's example, here is an alternative path to the top of the mountain.
library(terra)
f <- system.file("ex/elev.tif", package="terra")
x <- rast(f)
If there is a single maximum, you can do
g <- global(x, which.max)
xyFromCell(x, g[,1])
# x y
#[1,] 6.020833 50.17917
Now, consider a situation with multiple maxima. I add three more cells with the maximum value.
x[c(1000, 2500, 5000)] <- 547
We can find the four highest peaks with:
g <- global(x, which.max)[[1]]
v <- x[g] |> unlist()
y <- ifel(x == v, v, NA)
p <- as.points(y)
crds(p)
#[1,] 6.020833 50.17917
#[2,] 6.154167 50.10417
#[3,] 5.987500 49.97083
#[4,] 6.237500 49.75417
You should not warp (project
with terra) the raster data first because that changes the cell values and potentially the location of the highest peak. You should find the peaks with the original data, but then you can transform the results like this.
pp <- project(p, "EPSG:32636")
crds(pp)
# x y
#[1,] -1411008 5916157
#[2,] -1404896 5904422
#[3,] -1422145 5894509
#[4,] -1413735 5864236
With your files, you could start with something like
ff <- c("srtm_43_06.tif", "srtm_44_06.tif")
v <- vrt(ff)
g <- global(x, which.max)
And then continue as in the examples above.
Upvotes: 2