Reputation: 101
I am using the below function to get number of duplicated values in an array.But i want to get this result sorted descending order with respect to the values.
function countRequirementIds() {
const counts = {};
const sampleArray = RIDS;
sampleArray.forEach(function(x) { counts[x] = (counts[x] || 0) + 1; });
console.log(typeof counts); //object
return counts
}
Output:
{
"1": 4,
"2": 5,
"4": 1,
"13": 4
}
required output:
{
"2": 5,
"1": 4,
"13": 4,
"4": 1,
}
Upvotes: 0
Views: 1444
Reputation: 555
Javascript object keys are unordered as explained here: Does JavaScript guarantee object property order?
So sorting objects by keys is impossible. However if order is of a matter for you I would suggest using array of tuples:
const arrayOfTuples = [
[ "1", 4],
[ "2", 5],
[ "4", 1],
[ "13", 4],
]
arrayOfTuples.sort((a,b) => b[1] - a[1]);
console.log(arrayOfTuples);
// => [ [ '2', 5 ], [ '1', 4 ], [ '13', 4 ], [ '4', 1 ] ]
Upvotes: 1
Reputation: 101
The sort command. https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort Arrays of objects can be sorted by comparing the value of one of their properties.
Upvotes: 0