Reputation: 885
I am learning how to create a function in R, but I am struggling to understand how to write for
loop. My understanding is that
for (item I list_items) {
do_something(itemn)
}
I would like to write a for loop to replace with 333
the cells that are equal with 123
. So the item is 123
and the list of items is the df from sec1 till sec4
.
Could somebody explain this to me, please? And how this can be included in a function?
Sample code:
structure(list(sec1 = c(1, 123, 1), sec2 = c(123, 1, 1), sec3 = c(123,
0, 0), sec4 = c(1, 123, 1)), spec = structure(list(cols = list(
sec1 = structure(list(), class = c("collector_double", "collector"
)), sec2 = structure(list(), class = c("collector_double",
"collector")), sec3 = structure(list(), class = c("collector_double",
"collector")), sec4 = structure(list(), class = c("collector_double",
"collector"))), default = structure(list(), class = c("collector_guess",
"collector")), delim = ","), class = "col_spec"), row.names = c(NA,
-3L), class = c("spec_tbl_df", "tbl_df", "tbl", "data.frame"))
Upvotes: 0
Views: 61
Reputation: 11
in addition to DaveArmstrong Answer this would work for all rows and columns:
dat <- structure(list(sec1 = c(1, 123, 1), sec2 = c(123, 1, 1), sec3 = c(123,
0, 0), sec4 = c(1, 123, 1)), spec = structure(list(cols = list(
sec1 = structure(list(), class = c("collector_double", "collector"
)), sec2 = structure(list(), class = c("collector_double",
"collector")), sec3 = structure(list(), class = c("collector_double",
"collector")), sec4 = structure(list(), class = c("collector_double",
"collector"))), default = structure(list(), class = c("collector_guess",
"collector")), delim = ","), class = "col_spec"), row.names = c(NA,
-3L), class = c("spec_tbl_df", "tbl_df", "tbl", "data.frame"))
for(i in 1:nrow(dat)){
for(j in 1:ncol(dat)){
dat[i,j] <- ifelse(dat[i,j] == 123, 333, dat[i,j])
}
}
Upvotes: 1
Reputation: 21757
Here's how it would work for one column of your data:
dat <- structure(list(sec1 = c(1, 123, 1),
sec2 = c(123, 1, 1),
sec3 = c(123, 0, 0),
sec4 = c(1, 123, 1)),
spec = structure(list(cols = list(
sec1 = structure(list(),
class = c("collector_double", "collector")),
sec2 = structure(list(),
class = c("collector_double","collector")),
sec3 = structure(list(),
class = c("collector_double", "collector")),
sec4 = structure(list(),
class = c("collector_double","collector"))),
default = structure(list(),
class = c("collector_guess","collector")),
delim = ","), class = "col_spec"),
row.names = c(NA,-3L), class =
c("spec_tbl_df", "tbl_df", "tbl", "data.frame"))
for(i in 1:nrow(dat)){
dat$sec1[i] <- ifelse(dat$sec1[i] == 123, 333, dat$sec1[i])
}
dat
#> sec1 sec2 sec3 sec4
#> 1 1 123 123 1
#> 2 333 1 0 123
#> 3 1 1 0 1
Created on 2022-01-31 by the reprex package (v2.0.1)
To replace all of them, using for
loops, you could do a double loop over columns and rows.
for(j in names(dat)){
for(i in 1:nrow(dat)){
dat[[j]][i] <- ifelse(dat[[j]][i] == 123, 333, dat[[j]][i])
}
}
Of course, as others have identified, you certainly don't need a for loop to accomplish this.
Upvotes: 2
Reputation: 9858
We do not need a for loop here:
df[df==123]<-333
If we really need for loops:
for(i in 1:ncol(df)){
df[i][df[i]==123] <-333
}
output
df
# A tibble: 3 x 4
sec1 sec2 sec3 sec4
<dbl> <dbl> <dbl> <dbl>
1 1 333 333 1
2 333 1 0 333
3 1 1 0 1
Upvotes: 3