CODEWITHSUNDEEP
python
christine
christine

Reputation: 11

How to ignore values that are divided by zero

My values can't be divided by zero. However, I would still like to run the other values. Is there a solution to this? I have done some research and I know that people uses np.errstate and np.where, but I am not sure how to apply that to my code.

diesel_electric = [0,0,0,0,0,0,0,6,17,23,22,22,21]
electric = [1,1,1,1,2,2,3,0,1,1,12,314,560]
year = [2006,2007,2008,2009,2010,2011,2012,2013,2014,2015,2016,2017,2018]

fuels = input('Please select a fuel type: ')
if fuels in ['1']:
    for i in range(len(electric)):
        per = (electric[i]-electric[i-1])/electric[i-1]*100
        if per>= 6:
            print(f"{year[i]} {electric[i]}")
                 
elif fuels in ['2']:
    for i in range(len(diesel_electric)):
        per = (diesel_electric[i]-diesel_electric[i-1])/diesel_electric[i-1]*100
        if per>= 6:
            print(f"{year[i]} {diesel_electric[i]}")

Upvotes: 0

Views: 568

Answers (4)

Henrique Mello
Henrique Mello

Reputation: 11

The problem seems to be in the diesel_electric list, so you can just check if it is zero before doing the computation:

for i in range(len(diesel_electric)):
    if diesel_electric[i-1] != 0:
        per = (diesel_electric[i]-diesel_electric[i-1])/diesel_electric[i-1]*100
        if per>= 6:
            print(f"{year[i]} {diesel_electric[i]}")
    else:
        continue

It seems, though, that you'll find an aerror anyway because when i==0, then i-1 = -1, which isn't a valid index. So I'd say you start the loop from i = 1 in both loops:

for i in range(1,len(diesel_electric)):
    if diesel_electric[i-1] != 0:
        per = (diesel_electric[i]-diesel_electric[i-1])/diesel_electric[i-1]*100
        if per>= 6:
            print(f"{year[i]} {diesel_electric[i]}")
    else:
        continue

Upvotes: 1

DanielGzgzz
DanielGzgzz

Reputation: 118

you could use try: and except: to ignore or catch errors such as these, or just make some if and else statments to trace division by zero and skipping it

here is an example with try:

diesel_electric = [0,0,0,0,0,0,0,6,17,23,22,22,21]
electric = [1,1,1,1,2,2,3,0,1,1,12,314,560]
year = [2006,2007,2008,2009,2010,2011,2012,2013,2014,2015,2016,2017,2018]

fuels = input('Please select a fuel type: ')
if fuels in ['1']:
    for i in range(len(electric)):
        try:
            per = (electric[i]-electric[i-1])/electric[i-1]*100
            if per>= 6:
                print(f"{year[i]} {electric[i]}")
        except:
            pass
                 
elif fuels in ['2']:
    for i in range(len(diesel_electric)):
        try:
            per = (diesel_electric[i]-diesel_electric[i-1])/diesel_electric[i-1]*100
            if per>= 6:
                print(f"{year[i]} {diesel_electric[i]}")
        except:
            pass

running in IDLE

Upvotes: 0

Sarim Sikander
Sarim Sikander

Reputation: 406

Either you can apply a "if" condition to remove all zero values from processing. or you can take your code and insert it in a try and except block. that will not return any error for dividing by zero.

try:
    print 1/0
except ZeroDivisionError:
    print "You can't divide by zero!"

Upvotes: 2

fgoudra
fgoudra

Reputation: 861

You can use a try/except statement with the ZeroDivisionError:

try:
    # some calculation
    1 / 0
except ZeroDivisionError:
    pass

Upvotes: 1

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