Reputation: 61
I have the following DataFrame
import pandas as pd
d = {'Client':[1,2,3,4],'Salesperson':['John','John','Bob','Richard'],
'Amount':[1000,1000,0,500],'Salesperson 2':['Bob','Richard','John','Tom'],
'Amount2':[400,200,300,500]}
df = pd.DataFrame(data=d)
Client | Salesperson | Amount | Salesperson | Amount2 |
---|---|---|---|---|
1 | John | 1000 | Bob | 400 |
2 | John | 1000 | Richard | 200 |
3 | Bob | 0 | John | 300 |
4 | Richard | 500 | Tom | 500 |
And I just need to create some sort of "sumif" statement (the one from excel) that will add the amount each salesperson is due. I don't know how to iterate over each row, but I want to have it so that it adds the values in "Amount" and "Amount2" for each one of the salespersons.
Then I need to be able to see the amount per salesperson.
Expected Output (Ideally in a DataFrame as well)
Sales Person | Total Amount |
---|---|
John | 2300 |
Bob | 400 |
Richard | 700 |
Tom | 500 |
Upvotes: 1
Views: 426
Reputation: 38415
There can be multiple ways of solving this. One option is to use Pandas Concat
to join required columns and use groupby
merged_df = pd.concat([df[['Salesperson','Amount']], df[['Salesperson 2', 'Amount2']].rename(columns={'Salesperson 2':'Salesperson','Amount2':'Amount'})])
merged_df.groupby('Salesperson',as_index = False)['Amount'].sum()
you get
Salesperson Amount
0 Bob 400
1 John 2300
2 Richard 700
3 Tom 500
Edit: If you have another pair of salesperson/amount, you can add that to the concat
d = {'Client':[1,2,3,4],'Salesperson':['John','John','Bob','Richard'],
'Amount':[1000,1000,0,500],'Salesperson 2':['Bob','Richard','John','Tom'],
'Amount2':[400,200,300,500], 'Salesperson 3':['Nick','Richard','Sam','Bob'],
'Amount3':[400,800,100,400]}
df = pd.DataFrame(data=d)
merged_df = pd.concat([df[['Salesperson','Amount']], df[['Salesperson 2', 'Amount2']].rename(columns={'Salesperson 2':'Salesperson','Amount2':'Amount'}), df[['Salesperson 3', 'Amount3']].rename(columns={'Salesperson 3':'Salesperson','Amount3':'Amount'})])
merged_df.groupby('Salesperson',as_index = False)['Amount'].sum()
Salesperson Amount
0 Bob 800
1 John 2300
2 Nick 400
3 Richard 1500
4 Sam 100
5 Tom 500
Edit 2: Another solution using pandas wide_to_long
df = df.rename({'Salesperson':'Salesperson 1','Amount':'Amount1'}, axis='columns')
reshaped_df = pd.wide_to_long(df, stubnames=['Salesperson','Amount'], i='Client',j='num', suffix='\s?\d+').reset_index(drop = 1)
The above will reshape df,
Salesperson Amount
0 John 1000
1 John 1000
2 Bob 0
3 Richard 500
4 Bob 400
5 Richard 200
6 John 300
7 Tom 500
8 Nick 400
9 Richard 800
10 Sam 100
11 Bob 400
A simple groupby on reshaped_df will give you required output
reshaped_df.groupby('Salesperson', as_index = False)['Amount'].sum()
Upvotes: 3
Reputation: 28644
One option is to tidy the dataframe into long form, where all the Salespersons are in one column, and the amounts are in another, then you can groupby and get the aggregate.
Let's use pivot_longer from pyjanitor to transform to long form:
# pip install pyjanitor
import pandas as pd
import janitor
(df
.pivot_longer(
index="Client",
names_to=".value",
names_pattern=r"([a-zA-Z]+).*",
)
.groupby("Salesperson", as_index = False)
.Amount
.sum()
)
Salesperson Amount
0 Bob 400
1 John 2300
2 Richard 700
3 Tom 500
The .value
tells the function to keep only those parts of the column that match it as headers. The columns have a pattern (They start with a text - either Salesperson or Amount - and either have a number at the end ( or not). This pattern is captured in names_pattern
. .value
is paired with the regex in the brackets, those outside do not matter in this case.
Once transformed into long form, it is easy to groupby and aggregate. The as_index
parameter allows us to keep the output as a dataframe.
Upvotes: 0