CODEWITHSUNDEEP
python-3.xfastapipydantic
Mark Wardell
Mark Wardell

Reputation: 565

Problem: responseModel being ignored. FastApi (python 3.8)

I am using FastApi and My responseModel is being ignored. I am attempting to NOT return the password field in the response. Why does FastApi ignore my responsemodel definition?

Here is my api post method:

@app.post("/users")
def create_users(user: schemas.UserCreate, db: Session = Depends(get_db), response_model=schemas.UserOut):
    new_user = models.User(**user.dict())
    print(new_user)
    db.add(new_user)
    db.commit()
    db.refresh(new_user)
    return new_user

here is the postman return I should not see the password field:

{
    "password": "sdmfsladfj",
    "email": "[email protected]",
    "created_at": "2022-02-05T00:17:11.010020-06:00",
    "id": 10
}

Here is my responseModel definition in my schemas.py file:

class UserOut(BaseModel):
    id: int
    email: EmailStr
    created_at: datetime

    class Config:
        orm_mode = True




 anyio==3.5.0
    asgiref==3.5.0
    click==8.0.3
    dnspython==2.2.0
    email-validator==1.1.3
    emailvalidator==0.3
    fastapi==0.73.0
    greenlet==1.1.2
    h11==0.13.0
    idna==3.3
    psycopg2-binary==2.9.3
    pydantic==1.9.0
    sniffio==1.2.0
    SQLAlchemy==1.4.31
    sqlalchemy2-stubs==0.0.2a19
    sqlmodel==0.0.6
    starlette==0.17.1
    typing_extensions==4.0.1
    utcnow==0.3.0
    uvicorn==0.17.1

Upvotes: 0

Views: 254

Answers (1)

MatsLindh
MatsLindh

Reputation: 52902

response_model is an argument to the view decorator (since it's metadata about the view itself), not to the view function (which takes arguments that are necessary for how to process the view):

@app.post("/users", response_model=schemas.UserOut):
async def ...

Upvotes: 1

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