CODEWITHSUNDEEP
bashvariablesunix
Antilope
Antilope

Reputation: 445

set a dynamically created bash variable

Good morning, i need to dynamically change the name of a variable. I did some tests. my test script is this:

i=5
range5min=777
varname="range${i}min"
echo ${!varname}
#$`echo $varname`=555
$varname=555
echo $range5min

I can access its content with:

echo $ {! Varname}

But I can't set a dynamically created variable with a value, that is, I can't make the assignment of a value with the equal. I tried both of these ways:

$ `echo $ varname` = 555

$ varname = 555

What I would like to do is create new variables inside a for, depending on how many loops the for expects.

Upvotes: 3

Views: 61

Answers (1)

gniourf_gniourf
gniourf_gniourf

Reputation: 46823

you can use printf:

printf -v "$varname" '%s' "555"

Note, though, that this type of programming is not really recommended, since it makes code hard to read and understand.

An array or associative array might be more appropriate.

Upvotes: 3

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