CODEWITHSUNDEEP
pythonlistif-statementuser-inputin-function
Jean-Philippe Defrenne
Jean-Philippe Defrenne

Reputation: 21

Python if...in.. statement. Check for vowel in word

I'm trying to check if the user input contains a vowel or not. However, I've only found how to check for one vowel at a time, but not all.

vowel = ("a")

word = input("type a word: ")

if vowel in word:
 print (f"There is the vowel {vowel} in your word")
else:
 print ("There is no vowel in your word")

This seems to work but I get a error if I try to make the vowel variable into a list. ["a","e","i","o","u"]

any ideas how to check for e i o u at the same time?

Upvotes: 1

Views: 5206

Answers (6)

user18064043
user18064043

Reputation:

I can solve your problem. Here is the code:

vowels = {'a','e','i','o','u'}

word = input("Enter a word: ")

for vowel in word:

  if vowel in vowels:
    print(vowel,"is a vowel")

Upvotes: 0

Vincent
Vincent

Reputation: 1

I feel that if you want to use only if statements, then you can only choose one of the vowels but if you wish to use the for and if statements, it can go through with the whole vowels

Upvotes: 0

Mark Ransom
Mark Ransom

Reputation: 308101

A regular expression can tell you not only if there's a vowel in a string, but which vowels and their order.

>>> import re
>>> re.findall('[aeiou]', 'hello')
['e', 'o']

Upvotes: 1

coldy
coldy

Reputation: 2195

One way to keep track is also to have an existence list that keeps all vowels that exist in a word.

existence = []
vowels = ["a","e","i","o","u"]
test_word = "hello" # You can change this to receive input from user

for char in  test_word:
    if char in vowels:
        existence.append(char)
if existence and len(existence) > 0:
    for char in existence:
        print(f"These vowels exist in your input {test_word} - {char}")
else:
     print(f"There are no vowels existing in your input {test_word}")

Output:

These vowels exist in your input hello - e
These vowels exist in your input hello - o

Upvotes: 1

LeopardShark
LeopardShark

Reputation: 4416

If you do not need to know which vowels are present, you can use any as follows.

vowels = ("a", "e", "i", "o", "u")

word = input("type a word: ")

if any(v in word for v in vowels):
    print("There is at least one vowel in your word.")
else:
    print("There is no vowel in your word.")

Upvotes: 2

Mladen Milosavljevic
Mladen Milosavljevic

Reputation: 1810

you have to iterate over the list.

vowels =  ["a","e","i","o","u"]

word = input("type a word: ")

for vowel in vowels:
  if vowel in word:
     print (f"There is the vowel {vowel} in your word")
  else:
     print ("There is no vowel in your word")

iteration is the proces where you go through each item in a list.

for example.

list_a = ['a', 'b', 'c' ]

for item in list_a:
  print(item)

#output will be a b c

since other user complained in a comment. If you want to stop the loop after vowel found, you should add break statment

vowels =  ["a","e","i","o","u"]

word = input("type a word: ")

for vowel in vowels:
  if vowel in word:
     print (f"There is the vowel {vowel} in your word")
     break
  else:
     print ("There is no vowel in your word")

Upvotes: -1

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