CODEWITHSUNDEEP
c++c++11std
rin
rin

Reputation: 11

"pair" class made from "std::tuple"

I know that "std::pair" struct does not inherit from "std::tuple" class. However, I wanted to make "pair" class which inherited from "std::tuple" class.

Is this correct? Are there any other ways?

#include <tuple>

template <typename First, typename Second>
class pair : public std::tuple<First, Second> {
public:
  First &first = std::get<0>(*this);
  Second &second = std::get<1>(*this);

  using std::tuple<First, Second>::tuple;
};

Upvotes: 0

Views: 212

Answers (1)

eerorika
eerorika

Reputation: 238311

Is this correct?

Depends on what you intend to do with the class. If the intention is for it to work like std::pair, then it's not correct. Consider following example:

std::pair<int, int> std_p1{}, std_p2{};
std_p1 = std_p2; // works

pair<int, int> rin_p1{}, rin_p2{};
rin_p1 = rin_p2; // doesn't work

Are there any other ways?

Certainly. A good way is to not define a custom class inheriting from tuple, but to use std::pair instead. That said, I find it difficult to find any use cases for pair types in the first place as in most cases named classes tend to be superior.

Upvotes: 2

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