Reputation: 101
so I am trying to set up a nested filter on an array of objects. The thing is that the filter is applied inside the object on a key that is another array of objects.
here is the code:
const items = [
{ name: "123", id: 1, value: true, arr: [{ id: 1 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 2 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 3 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 4 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 5 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 6 }] },
];
const newArray = items.filter((objects) => {
objects.arr.filter((item) => {
if (item.id === 2) {
return objects;
}
});
});
console.log(newArray);
I 'm not sure where to put the return because in this situation i just get an empty array.
Upvotes: 5
Views: 4028
Reputation: 27192
As you contains only one object
in arr
then you can access this object by using [0]
index.
Working Demo :
const items = [
{ name: "123", id: 1, value: true, arr: [{ id: 1 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 2 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 3 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 4 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 5 }] },
{ name: "456", id: 2, value: false, arr: [{ id: 6 }] },
];
const newArray = items.filter((obj) => {
if (obj.arr[0].id === 2) {
return obj;
}
});
console.log(newArray);
I answered you as per the issue you are facing but if you have multiple objects in your arr
then you can go ahead with Array.some() method as suggested by other answers.
Upvotes: 1
Reputation: 28404
Use Array#some
to check if current arr
has an element with id
equal to 2:
const items = [ { name: "123", id: 1, value: true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] } ];
const newArray = items.filter(({ arr = [] }) =>
arr.some(({ id }) => id === 2)
);
console.log(newArray);
Upvotes: 2
Reputation: 386520
You need to check the nested array contains the wanted id
and return the result to the filter method.
const
items = [{ name: "123", id: 1, value: true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] }],
result = items.filter(({ arr }) => arr.some(({ id }) => id === 2));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Upvotes: 7