CODEWITHSUNDEEP
pythondiscord.py
yatharthStackOverflow
yatharthStackOverflow

Reputation: 13

Discord.py related stuff

when i try to create a command with "help" in it; it gives me an error so for example,

@client.command()
async def help():
    print("this works :)")

if i create a command called "help" it gives an error Traceback (most recent call last): File "C:\Users\DELL\Desktop\School Club Discord bot\main.py", line 12, in async def help(): File "C:\Users\DELL\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\ext\commands\core.py", line 1263, in decorator
self.add_command(result) File "C:\Users\DELL\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\ext\commands\core.py", line 1149, in add_command raise CommandRegistrationError(command.name) discord.ext.commands.errors.CommandRegistrationError: The command help is already an existing command or alias.

Upvotes: 0

Views: 69

Answers (1)

RoosterQMonee
RoosterQMonee

Reputation: 36

Discord.py already has a built-in help function. you can change it like this:

client = commands.Bot(command_prefix='!', help_command=None)

@client.command()
async def help():
    print("this works :)")

If you don't set help_command=None and try to create your help command it will default to the built-in command and it will use that instead.

Upvotes: 1

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