CODEWITHSUNDEEP
xmlparsinggroovynamespaces
Booyeoo
Booyeoo

Reputation: 583

Tutorial XML Parser Groovy Namespace Handling

i found this supergroovy function of XmlParser().parseText(...).

It works fine for me without namespaces... now i have the following XML (SoapRequest):

<?xml version="1.0" encoding="UTF-8"?>
   <soap:Envelope xmlns:soap="http://xxx" xmlns:xsd="http://xxy" 
     xmlns:xsi="http://xxz">
       <soap:Body>
         <MG_Input xmlns="http://yxx">
            <Accnr>001</Accnr> 
            [...]

My target is to acquire the Accnr over the XmlParser. I assumed that it could work this way:

input = new File('c:/temp/03102890.xml-out')

def soapns = new groovy.xml.Namespace("http://xxx",'soap')
def xsdns = new groovy.xml.Namespace("http://xxy")
def xsins = new groovy.xml.Namespace("http://xxz")
def ordns = new groovy.xml.Namespace("http://yxx")



xml = new XmlParser().parseText(input.getText())
println xml[soapns.Envelope][soapns.Body][ordns.MG_Input][Accnr][0].text()

But this doesnt really work...

Has anybody an idea of how to handle this 'easy'? I just cant get it to work with examples from google...

Upvotes: 5

Views: 12897

Answers (2)

Vins
Vins

Reputation: 2070

Tip for others:

you can just print the String that you parsed. for example, above print xml after this line xml = new XmlParser().parseText(input.getText()) , then you will get the top element, it will look similar to a JSON array, then you can easily traverse on that. Don't include the topmost element you see.

Upvotes: 1

winstaan74
winstaan74

Reputation: 1131

Your expression was incorrect - the xml var is already the root element of the xml document (in this case soap:Envelope) - so you just need to traverse from there. So, the expression you're looking for is:

println xml[soapns.Body][ordns.MG_Input].Accnr[0].text()

Upvotes: 8

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