CODEWITHSUNDEEP
pythondatetimetime
Integeek
Integeek

Reputation: 1

How split the time in python

I want to split the time for having the hours, the minutes, and the second on a list. But with the datetime module I can't. This is my code :

heure = datetime.now().time()
heure = heure.split(":")
print(heure)

Thank you in advance.

Upvotes: 0

Views: 2839

Answers (3)

Lucas Urban
Lucas Urban

Reputation: 655

There is a method called datetime.strftime, which also uses datetime like the method you tried to use. We change the string input to an integer using int().

from datetime import datetime as dt   # Import datetime module

now = dt.now()

# Using strftime to get the string into a global variable
year = now.strftime("%Y")
month = now.strftime("%m")
day = now.strftime("%d")
hour = now.strftime("%H")
minute = now.strftime("%M")
second = now.strftime("%S")
microseconds = now.strftime("%f")

# Turning the variables into integers
year = int(year)
month = int(month)
day = int(day)
hour = int(hour)
minute = int(minute)
second = int(second)
microseconds = int(microseconds)

# Putting the variables into a list
heure = [year, month, day, hour, minute, second, microseconds]

print(heure)

Indexes of the heure list

Index 0: Year

Index 1: Month

Index 2: Day

Index 3: Hour

Index 4: Minute

Index 5: Seconds

Index 6: Microseconds (1/1 000 000th of a second)

The only problem is that the time is in UTC, sadly, I do NOT know how to convert it using datetime.now().

Upvotes: 2

1tai
1tai

Reputation: 380

You need to convert the heure to string with the str() and then split it.

heure = datetime.now().time()
heure = str(heure).split(":")
print(heure)

Upvotes: 0

Samwise
Samwise

Reputation: 71454

heure is a datetime.time object, not a string. It already splits out the various components of the time as properties. Do:

>>> hms = [heure.hour, heure.minute, heure.second]
>>> hms
[8, 9, 33]

Upvotes: 1

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