CODEWITHSUNDEEP
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dipese
dipese

Reputation: 99

How do I create the same directory in every subdirectories in bash?

I've been trying to create the directory "a" inside all the subdirectories of "example".

What I tried is the following:

mkdir example/*/a

But it doesn't take the '*' as a wildcard, returning mkdir: can not create «example/*/a» directory: It doesn't exist file or directory

Note that I have too much subdirectories in example, so I can't do it by creating a list.

I don't want to do it with for loops, because I'm learning bash and I'm not allowed to use loops. Probably, there is no way to avoid a for loop, in that case, please tell me :).

Thank you.

Upvotes: 2

Views: 1510

Answers (4)

pjh
pjh

Reputation: 8064

Try:

dirs=( example/*/ )
mkdir -v "${dirs[@]/%/a}"
  • dirs=( example/*/ ) creates an array of all the subdirectories of example ( (example/dir1/ example/dir2/ ...) ).
  • "${dirs[@]/%/a}" expands to a list containing all the elements of dirs with an a appended to each of them ( (example/dir1/a example/dir2/a ...) ).

If you have a very large number of subdirectories the mkdir in the code above may fail with an "Argument list too long" error. See Argument list too long error for rm, cp, mv commands.

One way to avoid the problem is to pass a NUL-terminated list of the directories to be created to xargs -0:

dirs=( example/*/ )
printf '%s\0' "${dirs[@]/%/a}" | xargs -0 mkdir -v

That will, if necessary, run multiple mkdir commands, each with an argument list that does not exceed the limit.

However, if the number of directories is that large you may run into performance problems due to Bash (unnecessarily, but unavoidably) sorting the list produced by example/*/). In that case it would be better to use find. One way to do it is:

find example -maxdepth 1 -mindepth 1 -type d -printf '%p/a\0' | xargs -0 mkdir -v

find has built-in support for xargs-like behaviour with -exec ... +. However, it's a bit fiddly to use in this case. The best I can come up with in a hurry is:

find example -maxdepth 1 -mindepth 1 -type d    \
    -exec bash -c 'mkdir -v "${@/%//a}"' bash {} +

Since it adds /a to all of the arguments passed to bash by find before running mkdir on them, it may encounter an "Argument list too long" error anyway. I'll leave it here because it illustrates a sometimes-useful technique, but I recommend against using it.

Upvotes: 2

Costi Ciudatu
Costi Ciudatu

Reputation: 38195

I think you can only avoid a loop if you already know the subdirectories under example, e.g.:

mkdir example/{subdir1,subdir2,subdir3}/a

Otherwise, use a for loop to the rescue:

for d in example/*/; do mkdir "${d}a"; done

Note: add a -v to mkdir if you want it to show you the directories that get created.

Upvotes: 0

KamilCuk
KamilCuk

Reputation: 140970

Just:

for i in example/*/; do
    mkdir "$i"/a
done

Upvotes: 1

anubhava
anubhava

Reputation: 785068

Probably, there is no way to avoid a for loop

You can use find:

find example -type d -not -name a -exec mkdir -p {}/a \;

Upvotes: 2

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