CODEWITHSUNDEEP
ruby
NickP
NickP

Reputation: 1414

IF conditions not recognising in Ruby

I'm testing my basics of Ruby by writing a simple ChingChongCha program. One of my methods takes the choice entered and turns it into a number (for easy of use for future in the program) however this if statement keeps defaulting to the 'else' condition, even though I can see clearly that if rock is entered it matches the if condition perfectly with ROCK. Any ideas?

def user_choice(choice)
  # 1 is rock
  # 2 is paper
  # 3 is scissors
  userintchoice = 0
  choice.upcase!

  # turns user's choice into an integer
  puts choice #debugging
  if (choice == 'ROCK') then
    userintchoice = 1
  elsif (choice == 'PAPER') then
    userintchoice = 2
  elsif (choice == 'SCISSORS') then
    userintchoice = 3
  else
    puts "Invalid Choice!"
  end

  return userintchoice

end

Code calling this method and getting input is:

puts "What would you like to choose (input Rock, Paper or Scissors and <ENTER>)?"
userstringchoice = gets()
userchoice  = user_choice(userstringchoice)

Upvotes: 0

Views: 88

Answers (1)

Wukerplank
Wukerplank

Reputation: 4176

It seems you have to call .strip on userchoice because otherwise the string will contain a trailing \n.

Upvotes: 3

Related Questions