CODEWITHSUNDEEP
stringjavascript
Jibran
Jibran

Reputation: 930

JavaScript String Multiple Replace

I have a small web app where I need to perform text replacement in a string. However, the normal string.replace won't work. I am modifying portions of the text and then I need to put them back in the original string. For example, if I have:

var text = 'TEXT 000.99 001.00 TEXT'

and I need to add 0.01 to each of these numbers, I have an array of results:

var new_vals = [001.00, 001.01]

Then, when I try to replace 000.99 with 001.00, it will work and give me the following string:

text = 'TEXT 001.00 001.00 TEXT'

now I face the problem. The next replacement should be 001.00 <- 001.01, but doing so would result in:

text = 'TEXT 001.01 001.00 TEXT'

My question is, do you know of any JS library that provides a replace function that can perform multiple search/replace at the same time and on a copy of the string?

Upvotes: 1

Views: 755

Answers (3)

Digital Plane
Digital Plane

Reputation: 38264

Use str.replace with a function:

var text = 'TEXT 000.99 001.00 TEXT';
var new_vals = ["001.00", "001.01"];
var index = 0;
//Returns a new result string
var result = text.replace(/\b([\d.]+)\b/g, function(substr, num, offset, str){
  //See if the number is actually a number
  var num = parseFloat(num);
  //If not, return original
  if(isNaN(num))
    return substr;
  //Return the number from new_vals and increment the index
  else
    return new_vals[index++];
});
//result == "TEXT 001.00 001.01 TEXT"

Or, you could do the addition in the function:

var text = 'TEXT 000.99 001.00 TEXT';
//Returns a new result string
var result = text.replace(/\b([\d.]+)\b/g, function(substr, num, offset, str){
  //See if the number is actually a number
  var num = parseFloat(num);
  //If not, return original
  if(isNaN(num))
    return substr;
  //Return num+0.01 with 2 decimal places
  else
    return (num+0.01).toFixed(2);
});
//result == "TEXT 1.00 1.01 TEXT"

Upvotes: 3

secretformula
secretformula

Reputation: 6432

You could try split(' ') the values into an array. Then modifying the specific elements using a loop. Followed by join(' ') to join the text back into a string.

Upvotes: 0

Brett Walker
Brett Walker

Reputation: 3576

Try using the global replace regexp instead of a simple string. The simple string will replace only the first matching instance.

'TEXT 001.00 001.00 TEXT'.replace(/001.00/g, '001.01');

Upvotes: 0

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