CODEWITHSUNDEEP
python
Dan
Dan

Reputation: 169

If conditions with datetime comparisons

def countdown_date(strdate):
    datetimeobj = datetime.datetime.strptime(strdate, "%a, %b %d / %H:%M %p %Y")
    return datetimeobj - datetime.datetime.today()

My above functions asks for strdate and it expects data similar to this Sun, Dec 12 / 3:00 AM 2022 and the output will be a remaining count of days and hours til that date.

If the remaining days is a negative amount of days I'd like to increase the datetime object by one year and output the count

How do I do this?

Upvotes: 1

Views: 62

Answers (1)

user12734467
user12734467

Reputation:

To check the days remaining on your timedelta object, you can access the attribute days.

def countdown_date(strdate):
    datetimeobj = datetime.datetime.strptime(strdate, "%a, %b %d / %H:%M %p %Y")
    delta = datetimeobj - datetime.datetime.today()
    if delta.days < 0:
        ...  # do your thing
    return delta

Note here that delta is of type datetime.timedelta, and it ONLY holds days, seconds and microseconds. Hence, you can't increment the year value on it.

If you insist on incrementing a year on that timedelta, you can just add 365 days to it ...

def countdown_date(strdate):
    datetimeobj = datetime.datetime.strptime(strdate, "%a, %b %d / %H:%M %p %Y")
    delta = datetimeobj - datetime.datetime.today()
    if delta.days < 0:
        return delta + datetime.timedelta(days=365)
    return delta

Upvotes: 1

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