CODEWITHSUNDEEP
javascriptjqueryarraysjson
Alekc
Alekc

Reputation: 4770

Convert js Array() to JSon object for use with JQuery .ajax

in my app i need to send an javascript Array object to php script via ajax post. Something like this:

var saveData = Array();
saveData["a"] = 2;
saveData["c"] = 1;
alert(saveData);
$.ajax({
    type: "POST",
    url: "salvaPreventivo.php",
    data:saveData,
    async:true
    });

Array's indexes are strings and not int, so for this reason something like saveData.join('&') doesn't work.

Ideas?

Thanks in advance

Upvotes: 30

Views: 120235

Answers (5)

Tarun Gupta
Tarun Gupta

Reputation: 6403

There is actuly a difference between array object and JSON object. Instead of creating array object and converting it into a json object(with JSON.stringify(arr)) you can do this:

var sels = //Here is your array of SELECTs
var json = { };

for(var i = 0, l = sels.length; i < l; i++) {
  json[sels[i].id] = sels[i].value;
}

There is no need of converting it into JSON because its already a json object. To view the same use json.toSource();

Upvotes: 1

Ismael Tarqui
Ismael Tarqui

Reputation: 1

When using the data on the server, your characters can reach with the addition of slashes eg if string = {"hello"} comes as string = {\ "hello \"} to solve the following function can be used later to use json decode.

<?php
function stripslashes_deep($value)
{
    $value = is_array($value) ?
                array_map('stripslashes_deep', $value) :
                stripslashes($value);

    return $value;
}

$array = $_POST['jObject'];
$array = stripslashes_deep($array);

$data = json_decode($array, true);
print_r($data);
?>

Upvotes: 0

Shadrack Orina
Shadrack Orina

Reputation: 7953

If the array is already defined, you can create a json object by looping through the elements of the array which you can then post to the server, but if you are creating the array as for the case above, just create a json object instead as sugested by Paolo Bergantino

    var saveData = Array();
    saveData["a"] = 2;
    saveData["c"] = 1;
    
    //creating a json object
    var jObject={};
    for(i in saveData)
    {
        jObject[i] = saveData[i];
    }

    //Stringify this object and send it to the server
    
    jObject= YAHOO.lang.JSON.stringify(jObject);
    $.ajax({
            type:'post',
           cache:false,
             url:"salvaPreventivo.php",
            data:{jObject:  jObject}
    });
    
    // reading the data at the server
    <?php
    $data = json_decode($_POST['jObject'], true);
    print_r($data);
    ?>

    //for jObject= YAHOO.lang.JSON.stringify(jObject); to work,
    //include the follwing files

    //<!-- Dependencies -->
    //<script src="http://yui.yahooapis.com/2.9.0/build/yahoo/yahoo-min.js"></script>

    //<!-- Source file -->
    //<script src="http://yui.yahooapis.com/2.9.0/build/json/json-min.js"></script>

Hope this helps

Upvotes: 7

dstnbrkr
dstnbrkr

Reputation: 4335

You can iterate the key/value pairs of the saveData object to build an array of the pairs, then use join("&") on the resulting array: 

var a = [];
for (key in saveData) {
    a.push(key+"="+saveData[key]);
}
var serialized = a.join("&") // a=2&c=1

Upvotes: 4

Paolo Bergantino
Paolo Bergantino

Reputation: 488414

Don't make it an Array if it is not an Array, make it an object:

var saveData = {};
saveData.a = 2;
saveData.c = 1;

// equivalent to...
var saveData = {a: 2, c: 1}

// equivalent to....
var saveData = {};
saveData['a'] = 2;
saveData['c'] = 1;

Doing it the way you are doing it with Arrays is just taking advantage of Javascript's treatment of Arrays and not really the right way of doing it.

Upvotes: 65

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