Reputation: 31
For an example, I have a function foo()
int foo(const char* format,...) {
va_list args;
va_start(args, format)
...
va_end(args);
return bytes;
}
I have a format "%d%lf%s" and some arguments int a, double b and char* c is null-terminated string.
How to pull variables from args and calculate sizeof(a)+sizeof(b)+sizeof(c)
?
Upvotes: 3
Views: 141
Reputation: 241881
You cannot tell how many bytes were passed in the call, whatever that might mean. (Some arguments can be passed in registers. Some arguments might have padding between them.)
You can compute the sum of the sizeof
the expected arguments, but it's tedious. You need to parse the format string; every time you find a format specifier, you add the size of the expected corresponding argument. Make sure you take length modifiers into account; %llu
corresponds to sizeof(long long int)
, for example. However, %hu
corresponds to an unsigned short
which has been converted to an unsigned int
; whether you want to count that as sizeof(short)
or sizeof(int)
might depend on what you plan to do with the answer.
Upvotes: 2