Reputation: 538

Java XML parsing

Whats the quickest way to convert a doc like:

<customermodel:Customer>
    <creditCards>
        <cardNumber>@0</cardNumber>
        <provider>@HSBC</provider>
        <xsi:type>@customermodel:CreditCard</xsi:type>
             23242552
    </creditCards>
    .
    .

So that the elements with @ become attributes for the parent element.

ie get to:

<customermodel:Customer>
    <creditCards cardNumber="0" provider="HSBC" xsi-type="customermodel:CreditCard>
         232323232
    </creditCards>
        .
        .

Using a dom? or Sax parser or manually? and i can move the @ into the <>'s

Upvotes: 2

Answers (4)

jelovirt

Reputation: 5892

If you decide to use XSLT, it will look something like

  <!-- process element and attributes first so that whitespace doesn't interfere -->
  <xsl:template match="creditCards">
    <xsl:copy>
      <xsl:apply-templates select="* | @*"/>
      <xsl:apply-templates select="text()"/>
    </xsl:copy>    
  </xsl:template>

  <!-- change childrent of creditCards to attributes and strip first charcter from value -->
  <xsl:template match="creditCards/*">
    <xsl:attribute name="{name()}">
      <xsl:value-of select="substring(., 2)"/>
    </xsl:attribute>
  </xsl:template>

  <!-- rename xsi:type -->
  <xsl:template match="creditCards/xsi:type">
    <xsl:attribute name="xsi-type">
      <xsl:value-of select="substring(., 2)"/>
    </xsl:attribute>
  </xsl:template>

  <!-- identity transform -->
  <xsl:template match="node() | @*">
    <xsl:copy>
      <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
  </xsl:template>

Upvotes: 2