CODEWITHSUNDEEP
pythonsplit
Jeroen
Jeroen

Reputation: 841

python - splitting string by characters

I have a string which looks as such:

my_str = '15(1)(635)(634)(582)(583)'

How do I get an array of values from the string?

[15,1,635,634,582,583]

Upvotes: 1

Views: 1679

Answers (8)

Issam ELMACHEHOUR
Issam ELMACHEHOUR

Reputation: 1

your str looks like this:

my_str = '15(1)(635)(634)(582)(583)'

so replace ')' by space

mystr = mystr.replace(')'," ")

also replace '(' by space

mystr = mystr.replace(')'," ")

finally:

my_str = "15(1)(635)(634)(582)(583)"
mystr = my_str.replace(")", " ")
mystr = mystr.replace("(", " ")
mystr = [int(x) for x in mystr.split(" ") if x]
mystr

Upvotes: 0

Sumit S
Sumit S

Reputation: 606

There might be a shorter way. Here is one:

my_str = '15(1)(635)(634)(582)(583)'
my_str = my_str.replace(')(', ' ')
my_str = my_str.replace('(', ' ')
my_str = my_str.replace(')', ' ')
my_int_list = my_str.split()

Upvotes: 0

SRISANT PATI
SRISANT PATI

Reputation: 17

my_str = '15(1)(635)(634)(582)(583)'
new_str = my_str.replace("(", " ")
new_str = new_str.replace(")", " ")
my_arr = new_str.split()
my_arr = [int(num)for num in my_arr]
print(my_arr)

Upvotes: 0

Schnitte
Schnitte

Reputation: 1217

This is similar to this one. The preferred solution there was to replace all instances of one of the two delimiters with the other, e.g. by new_str = my_str.replace(')', '('), which gives you a string where you have only one kind of brackest as delimiter. Then a .split() on that with that delimiter, and you get a list, which you can easily convert into an array. If you want the individual values as integers rather than strings you'll also need to cast them.

Upvotes: 0

Aniketh Malyala
Aniketh Malyala

Reputation: 2660

You can use the re module:

import re
my_str = '15(1)(635)(634)(582)(583)'
my_str = re.findall(r"[\w']+", my_str)

for i in range(len(my_str)):
  my_str[i] = int(my_str[i])

print(my_str)

This will first split the list into Strings that are separated by special characters, then convert them to ints.

Alternatively, you can use a regular .split() function to split by "(", then remove the final ")" with substring:

my_str = '15(1)(635)(634)(582)(583)'
my_str = my_str.split("(")
for i in range(len(my_str) - 1):
  my_str[i + 1] = int(my_str[i + 1][:-1])

my_str[0] = int(my_str[0])
print(my_str)

Output for both:

[15, 1, 635, 634, 582, 583]

I hope this helped! Please let me know if you have any further questions or need clarification :)

Upvotes: 0

Samwise
Samwise

Reputation: 71424

Given this particular input, one way to simplify the problem is to just grab continguous strings of digits, e.g. using itertools.groupby:

>>> my_str = '15(1)(635)(634)(582)(583)'
>>> from itertools import groupby
>>> [int(''.join(group)) for dec, group in groupby(my_str, str.isdecimal) if dec]
[15, 1, 635, 634, 582, 583]

Upvotes: 0

S.B
S.B

Reputation: 16476

This can easily be solved with a simple regex : \d+

import re

my_str = '15(1)(635)(634)(582)(583)'
print([int(i.group()) for i in re.finditer(r'\d+', my_str)])

output:

[15, 1, 635, 634, 582, 583]

Upvotes: 2

Chris Sears
Chris Sears

Reputation: 6802

Remove the ")" and then split on "(":

[int(x) for x in my_str.replace(")", "").split("(")]

This list comprehension also converts the strings to ints.

Upvotes: 1

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