CODEWITHSUNDEEP
php
MLSALA
MLSALA

Reputation: 55

How to output from mysql base as json?

i tried this code but I can't

$row=$dbconnection->prepare ("select * from  fa");

$row->execute();

$data=array();

foreach ($row as $result)
{
    $data['movies'] = $result;
    array_push ($data, $isonformat);
}

echo json_encode ($data);   
?>

result

{"movies":{"name":"5","0":"5"},"0":null}

what I want {"movies": [ { "name":"5"} ] }

Upvotes: 0

Views: 66

Answers (1)

RiggsFolly
RiggsFolly

Reputation: 94662

Remove the array_push() and add an [] to the $data['movies'] = $result; to create a sub array

Also add

$row->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_OBJ);

or

$row->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);

to stop the resultset returning both object/array and numeric reference to each column. One of these should really be part of the connection script

$row->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_OBJ);

$row=$dbconnection->prepare ("select * from  fa");
$row->execute();

$data=array();

foreach ($row as $result) {
    $data['movies'][] = $result;
}

echo json_encode ($data);

Alternatively

$row->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_OBJ);
$row = $db->prepare ("select * from  articles");
$row->execute();

$data = [];

$data['movies'] = $row->fetchAll();
echo json_encode ($data);

Upvotes: 1

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