CODEWITHSUNDEEP
php
iPhoneJavaDev
iPhoneJavaDev

Reputation: 825

Disable submit button but not getting post data

I have the following code:

<?php
$post_test = filter_input(INPUT_POST, 'test');
if (isset($post_test)) {
    echo 'has data';
    // ********************
    // it is not going here
    // ********************
}

<form role="form" action="" method="post">
    // some form fields here
    <button type="submit" name="test" class="form-button" onclick="this.form.submit(); this.disabled=true; ">Send</button>
</form>

I want to disable the button when i submit. But it is not going inside the php code I highlighted above and there's no data. So I resorted to this just to fake the disabling:

<form role="form" action="" method="post">
    <button type="submit" name="test" class="form-button" onclick="this.className='button-disabled'; this.innerHTML='Sending...'; ">Send</button>
</form>

Please advise.

Updated

<?php
$post_test = filter_input(INPUT_POST, 'test');
if (isset($post_test)) {
    echo 'has data';
    // ********************
    // it is not going here
    // ********************
}
?>    

<form role="form" action="" method="post">
    // some form fields here
    <button type="submit" name="test" value="1" class="form-button" onclick="this.form.submit(); this.disabled=true; this.className='button-disabled'; this.innerHTML='Sending...'; ">Send</button>
</form>

Upvotes: 0

Views: 53

Answers (1)

Andrea Olivato
Andrea Olivato

Reputation: 2545

Instead of performing the check on the name of the submit button, create an hidden element with name test and value 1.

<form role="form" action="" method="post">
    <input type="hidden" name="test" value="1" />
    <button type="submit" class="form-button" onmouseup="this.form.submit();  this.disabled=true; this.className='button-disabled'; this.innerHTML='Sending...'; ">Send</button>
</form>

Upvotes: 1

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