CODEWITHSUNDEEP
python
Monk_1o1
Monk_1o1

Reputation: 21

python code is not giving output, can any body take a look, what may I have missed

It is not giving output, as expected, which says" {friend} is my friend", when {friend} is a string. And "you are not a name.......," when {friend} is a string.

Friends=["ankit","kanishk","manish","vansh","tanmay",34]
for friend in Friends:
      if friend is int:     
            print(f"you are not a name, you are a number {friend}")
      elif friend is str:
            print( friend.title()+" is  my friend.")

Upvotes: 0

Views: 50

Answers (3)

Abhyuday Vaish
Abhyuday Vaish

Reputation: 2379

What you are doing is checking the value as int and not the datatype of it. To check the datatype we have to use type().

>>> 34 is int
False
>>> type(34) == int
True

Friends=["ankit","kanishk","manish","vansh","tanmay",34]
for friend in Friends:
      if type(friend) == int:     
            print(f"you are not a name, you are a number {friend}")
      elif type(friend) == str:
            print( friend.title()+" is  my friend.")

Output:

Ankit is  my friend.
Kanishk is  my friend.
Manish is  my friend.
Vansh is  my friend.
Tanmay is  my friend.
you are not a name, you are a number 34

Upvotes: 0

rohithpoya
rohithpoya

Reputation: 1005

You can use isinstance like below,

Friends=["ankit","kanishk","manish","vansh","tanmay",34]
for friend in Friends:
      if isinstance(friend, int):     
            print(f"you are not a name, you are a number {friend}")
      elif isinstance(friend, str):
            print( friend.title()+" is  my friend.")

Upvotes: 0

Ibrahim Halici
Ibrahim Halici

Reputation: 52

Friends=["ankit","kanishk","manish","vansh","tanmay",34]
for friend in Friends:
      if type(friend) is int:
            print(f"you are not a name you are a number which is {friend}")
      elif type(friend)  is str:
            print( friend.title()+" is  my friend.")

you should add the 'type()' function for friend. friend's type is int or str.

Upvotes: 1

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