CODEWITHSUNDEEP
javascriptfirebasefirebase-realtime-database
Gaito Uchiha
Gaito Uchiha

Reputation: 85

Retrieve an child value and compare using firebase by javascript

    const uid = firebase.auth().currentUser.uid;

var query = firebase.database().ref("/user/").child(user.uid).orderByChild("l1").equalTo("bought ")
     query.on("value", function(snapshot) {
         var lg1=document.getElementById("lg1");
    var lg2=document.getElementById("lg2");
    var blg=document.getElementById("blg");
    lg2.style.display=" none";
    lg1.style.display="block"; 
    blg.style.display="block";
         
     });

I am comparing a child data in firebase realtime database and disable enable display using the snapshot function but it's not working I tried and research a lot but I couldn't find a perfect solution.

Any ideas on how to proceed above code?

Here is the screenshot of my firebase realtime database

Firebase realtime database

Upvotes: 0

Views: 139

Answers (1)

Frank van Puffelen
Frank van Puffelen

Reputation: 598765

Firebase queries work on the list of direct child nodes under the path that you query.

Since your query runs on /user/$uid, the nodes the query considers are email, l1, points and uid. For each of those it then looks for a child property l1 and compares the value to what you specified. But none of these four nodes has an l1 property.

If you want to be able to search the child nodes of /user/$uid for their l1 property, you need an extra level in the JSON, which is typically generated by calling push() as shown in the documentation on adding nodes to a list. So your JSON would become

user: {
  "$uid": {
    "$pushid": { // 👈 new
      email: "...",
      l1: "...",
      points: ...,
      uid: "...",
    }
  }
}

With that structure your query will work.

Upvotes: 1

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