Reputation: 636
Good day
The goal is to use the LSM9DS0 with a ST chip.
The situation is that the I2C address as returned by the scanner (ST environment) is not the same to that of Arduino I2C scanner. I am using a STM32 Nucleo-F429 and ESP32 devkit.
When I scan for I2C addresses using the below code, it returns the following four addresses:
0x3A
0x3B
0xD6
0xD7
However I have used this very IMU breakout on a ESP32 before and I noticed that the addresses are not the same. When I run the I2C scanning code I get the following addresses.
0x1D
0x6B
STM32 code: Src files were generated by CubeMX. Let me know if the i2c.h/c are required. But they should be pretty standard.
for (uint16_t i = 0; i < 255; i++)
{
if (HAL_I2C_IsDeviceReady(&hi2c1, i, 5, 50) == HAL_OK)
{
HAL_GPIO_TogglePin(LED_RED_PORT, LED_RED_PIN);
char I2cMessage[10];
sprintf(I2cMessage, "%d , 0x%X\r\n", i, i);
HAL_UART_Transmit(&huart2, (uint8_t *)I2cMessage, strlen(I2cMessage), 10);
}
}
Arduino code:
#include <Wire.h>
void setup()
{
Wire.begin();
Serial.begin(115200);
while (!Serial); // Leonardo: wait for serial monitor
Serial.println("\nI2C Scanner");
}
void loop()
{
byte error, address;
int nDevices;
Serial.println("Scanning...");
nDevices = 0;
for(address = 1; address < 127; address++ )
{
// The i2c_scanner uses the return value of
// the Write.endTransmisstion to see if
// a device did acknowledge to the address.
Wire.beginTransmission(address);
error = Wire.endTransmission();
if (error == 0)
{
Serial.print("I2C device found at address 0x");
if (address<16)
Serial.print("0");
Serial.print(address,HEX);
Serial.println(" !");
nDevices++;
}
else if (error==4)
{
Serial.print("Unknown error at address 0x");
if (address<16)
Serial.print("0");
Serial.println(address,HEX);
}
}
if (nDevices == 0)
Serial.println("No I2C devices found\n");
else
Serial.println("done\n");
delay(5000); // wait 5 seconds for next scan
}
Does anyone know why this is and is it a problem?
Upvotes: 0
Views: 1338
Reputation: 1911
one can find I2C devices on an ESP32 using the code below:
void I2Cscanner() {
Serial.println ();
Serial.println ("I2C scanner. Scanning ...");
byte count = 0;
Wire.begin();
for (byte i = 8; i < 120; i++)
{
Wire.beginTransmission (i); // Begin I2C transmission Address (i)
if (Wire.endTransmission () == 0) // Receive 0 = success (ACK response)
{
Serial.print ("Found address: ");
Serial.print (i, DEC);
Serial.print (" (0x");
Serial.print (i, HEX); // PCF8574 7 bit address
Serial.println (")");
count++;
}
}
Serial.print ("Found ");
Serial.print (count, DEC); // numbers of devices
Serial.println (" device(s).");
}
Upvotes: 0
Reputation: 636
I found the answer in the description of the HAL API. The API requires the 7bt address to be bit shifted to the left by 1bit.
Within the file: stm32F4xx_hal_i2c.c
the description of the HAL_I2C_IsDeviceReady()
API says the following:
* @param DevAddress Target device address: The device 7 bits address value
* in datasheet must be shifted to the left before calling the interface
Thus, change the IsDeviceReady arguments as follows and it will work.
for (uint16_t i = 0; i < 255; i++)
{
if (HAL_I2C_IsDeviceReady(&hi2c1, i<<1, 5, 10) == HAL_OK)
{
// Do crazy stuff
}
}
This worked for me. Hope it helps anyone with the same issue
Upvotes: 0