CODEWITHSUNDEEP
c#
salvatore20553
salvatore20553

Reputation: 3

Problem foreach Windows Forms in Visual Studio 2019

I have a problem, and my problem is the following: I have this code in C# and I don't know how to do a foreach to get all pakFilename

WebClient client = new WebClient();

string strpagecode = client.DownloadString("https://fortnite-api.com/v2/aes");
dynamic dobj = JsonConvert.DeserializeObject<dynamic>(strpagecode);
string description = dobj["data"]["dynamicsKeys"][0]["pakFilename"].ToString();
aes.Text = description;

Could someone help me?

Thank you very much in advance

Upvotes: 0

Views: 61

Answers (2)

Daniel
Daniel

Reputation: 9839

Maybe it would help to use real objects instead of dealing with dynamic.

Generate c# classes from the JSON. Paste your json string to a tool like https://json2csharp.com/.

The following classes are generated:

public class DynamicKey
{
    public string PakFilename { get; set; }
    public string PakGuid { get; set; }
    public string Key { get; set; }
}

public class Data
{
    public string Build { get; set; }
    public string MainKey { get; set; }
    public List<DynamicKey> DynamicKeys { get; set; }
    public DateTime Updated { get; set; }
}

public class Root
{
    public int Status { get; set; }
    public Data Data { get; set; }
}

Afterwards you could easily deal with these objects:

WebClient client = new WebClient();
string strpagecode = client.DownloadString("https://fortnite-api.com/v2/aes");
Root myDeserializedClass = JsonConvert.DeserializeObject<Root>(strpagecode);
List<string>? pakFileNames = myDeserializedClass.Data.DynamicKeys.Select(x => x.PakFilename).ToList();

// add to textbox
aes.text = string.Join("\n", pakFileNames);

This should give you the list of all pakFileNames: enter image description here

Upvotes: 1

Andr&#233; Brink
Andr&#233; Brink

Reputation: 108

Is this what you mean?

var dynamicsKeys = dobj["data"]["dynamicsKeys"];
foreach(var dynamicsKey in dynamicsKeys) {
    string pakFilename = dynamicsKeys["pakFilename"].ToString()
}

Upvotes: 1

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