CODEWITHSUNDEEP
mongodbmongodb-querypymongo
Mukul Varshney
Mukul Varshney

Reputation: 114

How to get matching subdocuments in mongodb

I have schema like this -

 {
   "_id":"ObjectId(""622f950e73043487031bb3ee"")",
   "outerTimeStamp" : "14-Mar-2022",
   "filtered":{
      "data":[
         {
            "Price":14350,
            "expiryDate":"17-Mar-2022",
            "info1":{
               "Price":14350,
               "expiryDate":"17-Mar-2022",
            },
            "info2":{
               "Price":14350,
               "expiryDate":"17-Mar-2022"
            }
         },
         {
            "Price":14350,
            "expiryDate":"17-Mar-2022",
            "info1":{
               "Price":14350,
               "expiryDate":"17-Mar-2022",
            },
            "info2":{
               "Price":14350,
               "expiryDate":"17-Mar-2022"
            }
         },
         ......
         ....
     ]
    }
}

I need all the subdocuments from a document where expiryDate == "17-Mar-2022"

I have used the following query -

db.collection.find({ "filtered.data" : { $elemMatch : { "expiryDate" : "17-Mar-2022"}} }, { "filtered.data.$" : 1 })

it just returns the first matching sub-document but there are many other documents also available

if I don't use ".$" then it returns all those documents even those that don't match with the query conditions.

thanks in advance

Upvotes: 0

Views: 744

Answers (1)

R2D2
R2D2

Reputation: 10727

You can do simpy by aggregation/$filter:

db.collection.aggregate([
{
  $match: {
  "filtered.data.expiryDate": "17-Mar-2022"
  }
},
{
 $addFields: {
  "filtered.data": {
    "$filter": {
      "input": "$filtered.data",
      "as": "d",
      "cond": {
        "$eq": [
          "$$d.expiryDate",
          "17-Mar-2022"
        ]
       }
     }
    }
  }
 }
])

For best results index need to be created on "filtered.data.expiryDate"

playground

Upvotes: 2

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